右键单击Listview大图标以打开ContextMenuStrip [英] Listview Large Icon right click to open ContextMenuStrip

问题描述

在我的项目中，我有一个ListView，当我单击大图标中的右键时，我想打开我的ContextMenuStrip.我尝试了很多事情，但没有成功.在ListView的内部单击鼠标右键时，会打开ContextMenuStrip，但是我想在右键单击大图标时看到它.

In my project I have a ListView and I would like to open my ContextMenuStrip when I clicked right button in the large icon. I tried many things but I am unsuccessful. When I right click inside of ListView the ContextMenuStrip opens, but I want to see just when I right clicked the large icon.

我还需要帮助来获取单击的图标的名称(属性).

Also I need to help about get the clicked icon's name (properties).

推荐答案

这是一种快速而肮脏的解决方案；请比我投入更多的工作.

This is a quick and dirty solution; please do put more work into it than I did..

// a class level reference, prepare it where you want..
ContextMenuStrip ms = new ContextMenuStrip();

您应该编写MouseDown或MouseUp事件的代码:

You should either code the MouseDown or the MouseUp event:

private void listView1_MouseDown(object sender, MouseEventArgs e)
{
    // disassociate from listview at first:
    listView1.ContextMenuStrip = null;

    // check for right button
    if (e.Button != System.Windows.Forms.MouseButtons.Right) return;

    // get item info:
    ListViewHitTestInfo hi = listView1.HitTest(e.Location);

    // no item hit:
    if (hi.Item == null) return;

    // calculate the image rectangle:

    // this contains the unscrolled y coordinate:
    Point iloc = listView1.GetItemRect(hi.Item.Index).Location;
    // we combine it with the x-position:
    Rectangle r = new Rectangle(new Point (hi.Item.Position.X,  iloc.Y),
                                imageList1.ImageSize);
    // no image hit:
    if ( !r.Contains(e.Location) ) return;

    // maybe prepare or change the menue now..
    // here I display the image name from the keys array:
    ms.Items[0].Text = imageList1.Images.Keys[hi.Item.ImageIndex];
    ms.Location = e.Location;

    // associate with listview and show
    listView1.ContextMenuStrip = ms;
    ms.Show();
}

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