Android的MediaStore与TITLE_KEY比较得到的光标位置 [英] Android MediaStore get cursor position by comparing with TITLE_KEY

问题描述

我使用MediaStore的媒体内容，并有一个搜索查看过滤在listfragment显示的内容。

I am using MediaStore's media content and have a SearchView to filter the content displayed in a listfragment.

我把（ mainCursor ）将光标引用当查询字符串为空（这意味着所有行）
当用户搜索，我得到基于查询新的光标

I keep a reference to the cursor(mainCursor) when the query string is null (which means all rows) When user searches, i get new cursor based on the query

按我的理解（我很新的光标，DB＆安培; ContentProvider的），光标将包含匹配查询和列查询所有行是 MediaStore.Audio.Media.TITLE ，这样我就可以看到列表匹配的标题。

As per my understanding(I am very new to Cursor,DB & Contentprovider), the cursor will contain all the rows matching the query and the column to query is MediaStore.Audio.Media.TITLE, so i can see matching titles in list.

public void doQuery(String query) {
    // TODO Auto-generated method stub
    Log.e(TAG,"inside doQuery: "+query);
    String search = MediaStore.Audio.Media.TITLE + " LIKE '%" + query + "%'";
    Cursor cursorNew = getContentResolver().query(MediaStore.Audio.Media.EXTERNAL_CONTENT_URI,columns, search , null, MediaStore.Audio.Media.DEFAULT_SORT_ORDER);
    sendBroadcast(new Intent(MainActivity.SWAP_CURSOR));

}

现在，当用户presses列表元素，I 为getPosition（）光标并检索 TRACK_ID 的选择的项目。

Now when user presses list element, i getPosition() of the cursor and retrieve the TRACK_ID of selected item.

我的问题是：如何寻找最初的光标，即 mainCursor 与 TRACK_ID 从获得 cursorNew 和来获得mainCursor匹配TRACK_ID的位置？
我不想 SELECT 从mainCursor，因为我想从非过滤的光标获取特定轨道的位置

My question is: How to search the initial cursor, i.e., mainCursor with TRACK_ID got from cursorNew and to get the position of the matching TRACK_ID in mainCursor? I don't want to SELECT from the mainCursor, because i want to get the position of a specific TRACK from the un-filtered cursor

在此先感谢

推荐答案

如果你在的位置有兴趣，你为什么不把audio_ids阵列中的

If you are just interested in the position, why dont you put the audio_ids in an array

     ArrayList<String> audio_ids = new ArrayList<String>();

    for (cursor.moveToFirst(); !cursor.isAfterLast(); cursor.moveToNext()){
        String audio_id =     cursor.getString(cursor.getColumnIndex(MediaStore.Audio.Playlists.Members.AUDIO_ID));
        audio_ids.add(audio_id);
    }

，然后用

        String audio_id = cursor.getString(cursor.getColumnIndex(MediaStore.Audio.Playlists.Members.AUDIO_ID));
        position = audio_ids.lastIndexOf(audio_id);

此示例查询播放列表。上面的例子能给你的最后一个位置，如果你有重复。 （你也许没有想过？）
我希望这给你一些想法

This example queries playlists. The above example would give you the last position if you had duplicates. (something you perhaps had not thought about?) I hope this gives you some ideas

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