在共享主机上用php启动websockets服务器 [英] starting a websockets server in php on shared hosting

问题描述

我有一个使用WebSockets在PHP中实现的聊天应用程序( http://code. google.com/p/phpwebsocket/)，然后在我的本地主机上进行测试时，我必须通过命令"php server.php"运行WebSockets服务器，该命令将在本地主机上启动服务器，并且文件一直运行直到我按我的Ubuntu终端上的"Ctrl + c".我的意思是它继续运行while循环，这是非常正常的bcoz，服务器应该可以监听请求.

I have a chat application implemented in PHP using WebSockets (http://code.google.com/p/phpwebsocket/), and on my localhost when i test it i have to run the WebSockets server through a command "php server.php", which starts the server on localhost and the file keeps running till i press "Ctrl + c" on my Ubuntu terminal. I mean it keeps on running the while loop, which is quite normal bcoz the server should be up to listen to the requests.

现在，我的疑问是我已将此应用程序托管在共享主机上，但该主机没有授予我SSH访问权限，我的意思是我无法获得以前用于运行命令的界面之类的终端，因此我将如何运行那个server.php脚本现在启动我的服务器?

Now my doubt is that i have hosted this application on a shared hosting, which does not give me SSH access, i mean i cannot get a terminal like interface where i used to run my command, so HOW will i run that server.php script to start my server now?

是的，我提到的一件事我只需要运行一次脚本，然后脚本将继续运行，并且托管提供程序还允许设置cron jobs.

And yes one thing that i mentioned i just need to run the script once, then the script will keep on running, and also the hosting provider allows to set up cron jobs.

请帮助，谢谢.

推荐答案

无法通过SSH访问您的共享托管非常困难.那就是...

Not having SSH access to your shared hosting is pretty flaky. That said...

您可以使用 exec 在命令行上从触发脚本.例如，如果您有一个控制器操作，而该操作是从类似 http://mysite.com/server/start的URL调用的，您可以嵌入该行:

You can use exec to run something on the command line from a triggered script. For instance, if you have a controller action that you call from a URL like http://mysite.com/server/start, you could embed the line:

$lastLine = exec("php server.php");

当然，该命令将在命令完成后才会返回，因此您永远不会从此脚本获得响应(除非失败).因此，我将使用 popen ，它将分叉该过程并立即返回，让您的控制器返回响应.

Of course, this command will not return until the command finishes, so you will never get a response from this script (unless it fails). So I would use popen, which will fork the process and return right away, allowing your controller to return a response.

$handle = popen("php server.php", "r");

在某个时候，您可能要停止该服务器.您可以使用 passthru 和 http://mysite.com/server/stop 一样，您可以嵌入:

At some point, you are probably going to want to stop this server. You can use passthru and posix_kill with a little unix CLI magic to get this done, maybe in another controller action that you call from a URL like http://mysite.com/server/stop, you could embed:

$output = passthru('ps ax | grep server\.php');
$ar = preg_split('/ /', $output);
if (in_array('/usr/bin/php', $ar)) {
    $pid = (int) $ar[0];
    posix_kill($pid, SIGKILL);

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