使用lodash来比较数组(项目存在而没有顺序) [英] using lodash to compare arrays (items existence without order)

问题描述

我知道我可以使用循环来做到这一点，但是我正在尝试找到一种优雅的方式来做到这一点:

I know I can do it using loops, but I am trying to find an elegant way of doing this:

我有两个数组:

var array1 = [['a', 'b'], ['b', 'c']];
var array2 = [['b', 'c'], ['a', 'b']];

我想用lodash确认两者相同. 相同"是指array1中没有未包含在array2中的项目.

I want to use lodash to confirm that the two are the same. By 'the same' I mean that there is no item in array1 that is not contained in array2.

在检查这些项目之间的相等性方面:

In terms of checking equality between these items:

['a', 'b'] == ['b', 'a'] 

或

['a', 'b'] == ['a', 'b'] 

因为字母始终是有序的，所以两者都可以工作.

both work since the letters will always be in order.

提前谢谢.

推荐答案

如果对外部数组进行排序，则可以使用 _.isEqual() ，因为内部数组已经排序.

If you sort the outer array, you can use _.isEqual() since the inner array is already sorted.

var array1 = [['a', 'b'], ['b', 'c']];
var array2 = [['b', 'c'], ['a', 'b']];
_.isEqual(array1.sort(), array2.sort()); //true

请注意，.sort()将使数组变异.如果这对您来说是个问题，请首先使用(例如).slice()或传播运算符(...)进行复制.

Note that .sort() will mutate the arrays. If that's a problem for you, make a copy first using (for example) .slice() or the spread operator (...).

或者，按照丹尼尔·布迪克(Daniel Budick)在以下评论中建议的方式进行操作:

Or, do as Daniel Budick recommends in a comment below:

_.isEqual(_.sortBy(array1), _.sortBy(array2))

Lodash的sortBy()不会使数组变异.

Lodash's sortBy() will not mutate the array.

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