替换数组中的对象 [英] Replacing objects in array

问题描述

我有这个javascript对象:

I have this javascript object:

var arr1 = [{id:'124',name:'qqq'}, 
           {id:'589',name:'www'}, 
           {id:'45',name:'eee'},
           {id:'567',name:'rrr'}]

var arr2 = [{id:'124',name:'ttt'}, 
           {id:'45',name:'yyy'}]

我需要用相同 id 的 arr2 中的项目替换 arr1 中的对象.

I need to replace objects in arr1 with items from arr2 with same id.

这就是我想要得到的结果:

So here is the result I want to get:

var arr1 = [{id:'124',name:'ttt'}, 
           {id:'589',name:'www'}, 
           {id:'45',name:'yyy'},
           {id:'567',name:'rrr'}]

如何使用javascript实现它?

How can I implement it using javascript?

推荐答案

您可以使用 Array#find .

You can use Array#map with Array#find.

arr1.map(obj => arr2.find(o => o.id === obj.id) || obj);

var arr1 = [{
    id: '124',
    name: 'qqq'
}, {
    id: '589',
    name: 'www'
}, {
    id: '45',
    name: 'eee'
}, {
    id: '567',
    name: 'rrr'
}];

var arr2 = [{
    id: '124',
    name: 'ttt'
}, {
    id: '45',
    name: 'yyy'
}];

var res = arr1.map(obj => arr2.find(o => o.id === obj.id) || obj);

console.log(res);

此处，如果在arr2中找到id，则arr2.find(o => o.id === obj.id)将从arr2返回元素，即对象.如果不是，则返回arr1中相同的元素，即obj.

Here, arr2.find(o => o.id === obj.id) will return the element i.e. object from arr2 if the id is found in the arr2. If not, then the same element in arr1 i.e. obj is returned.

这篇关于替换数组中的对象的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！