在数组数组上使用唯一的lodash [英] using lodash unique on an array of arrays

问题描述

我不确定如何使用它从主阵列中删除重复的阵列.因此请考虑以下几点:

I am not sure how to use this to remove duplicate arrays from the main array. so consider the following:

var arr = [
    [0, 1],
    [0, 1],
    [2, 1],
];

结果数组应如下所示:

var arr = [
    [0, 1],
    [2, 1],
];

该文档对单个元素数组有意义，但对于2d数组则没有意义.

The documentation makes sense for a single array of elements but not a 2d array.

想法?

要变为唯一的数组可能具有:

The array to be turned unique might have:

var arr = [
  [0, 1]
  [0, 2]
  [0, 3]
  [0, 1]
  [2, 1]
]

该数组旁边的数组应该具有所有值进行比较，因此在上面的示例中，它应该吐出:

the array in side the array should have all value compared, so in the above example, it should spit out:

var arr = [
  [0, 1]
  [0, 2]
  [0, 3]
  [2, 1]
]

重复项为[0, 1]

推荐答案

最简单的方法可能是使用uniq方法，然后将内部数组转换为某些字符串表示形式，JSON.stringify应该是足够好的解决方案.

The easiest way would probably be to use uniq method and then convert the inner arrays to some string representation, JSON.stringify should be good enough solution.

var arr = [[0, 1], [0, 2], [0, 3], [0, 1], [2, 1]]
_.uniq(arr, function(item) { 
    return JSON.stringify(item); 
});
// [[0,1], [0,2], [0,3], [2,1]]

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