记录模块未写入文件 [英] Logging module not writing to file

问题描述

我正在使用logging模块，并且传入了与当前正在执行的其他作业相同的参数:

I'm using logging module, and I've passed in the same parameters that I have on other jobs that are currently working:

import logging
from inst_config import config3

logging.basicConfig(
    level=logging.INFO,
    format='%(asctime)s [%(levelname)s] - %(message)s',
    filename=config3.GET_LOGFILE(config3.REQUESTS_USAGE_LOGFILE))
logging.warning('This should go in the file.')

if __name__ == '__main__':
    logging.info('Starting unload.')

使用此方法创建文件名:

Using this method to create the filename:

REQUESTS_USAGE_LOGFILE = r'C:\RunLogs\Requests_Usage\requests_usage_runlog_{}.txt'.format(
        CUR_MONTH)
def GET_LOGFILE(logfile):
    """Truncates file and returns."""
    with open(logfile, 'w'):
        pass
    return logfile

但是，当我运行它时，它正在创建文件，然后仍然将日志记录信息输出到控制台.我正在Powershell中运行.

When I run it, however, it is creating the file, and then still outputting the logging info to the console. I'm running in Powershell.

只需尝试将其放在主语句中，如下所示:

Just tried putting it inside the main statement like this:

if __name__ == '__main__':
    logging.basicConfig(
    level=logging.INFO,
    format='%(asctime)s [%(levelname)s] - %(message)s',
    filename=config3.GET_LOGFILE(config3.REQUESTS_USAGE_LOGFILE))

    logging.warning('This should go in the file.')

还是没有运气.

推荐答案

您可以尝试在主文件中运行它吗?

Can you try run this in your main file:

import logging 
logging.basicConfig(
    level=logging.INFO, 
    format='%(asctime)s [%(levelname)s] - %(message)s',
    filename='filename.txt')  # pass explicit filename here 
logger = logging.get_logger()  # get the root logger
logger.warning('This should go in the file.')
print logger.handlers   # you should have one FileHandler object

这篇关于记录模块未写入文件的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！