我的日志记录类中的异常行为 [英] Strange behaviour on my logging class
问题描述
我会尽量恢复.我有我写的这堂课:
I will try to resume as much as possible. I have this class I wrote:
import logging, logging.handlers.TimedRotatingFileHandler
class Logger(object):
def __init__(self, log_filename):
logging.basicConfig(format='%(asctime)s %(message)s')
formatter = logging.Formatter('%(asctime)s - %(levelname)s - %(message)s')
loghandler = TimedRotatingFileHandler(
log_filename, when="midnight", backupCount=50
)
loghandler.setFormatter(formatter)
self.logger = logging.getLogger()
self.logger.setLevel(logging.INFO)
self.logger.addHandler(loghandler)
def getLogger(self):
return self.logger
它确实运行良好,现在当我有一个使用Logger实例的脚本时出现了问题,并且在该脚本中我也实例化了一个使用Logger的类,如下所示:
It works good indeed, now the problem arises when I have a script that uses a Logger instance and within that script I instantiate a class that uses a Logger too, something like this:
import ClassA
A = ClassA()
log = Logger(log_filename='script_logger.log')
logger = log.getLogger()
logger.info('Initiated Script')
while True:
logger.info('Looping')
A.run()
我的班级样子:
class ClassA(object):
def __init__(self):
log = Logger(log_filename='class_logger.log')
self.logger = log.getLogger()
self.logger.info('Started ClassA')
def run(self):
self.logger.info('Into method run')
现在,我希望有2个单独的日志文件,class_logger.log
和script_logger.log
可以正常工作,但是两个文件的内容逐行完全相同.
Now I expect to have 2 separate log files, class_logger.log
and script_logger.log
that works OK, but both files have exactly the same content line by line.
所以script_logger.log
和class_logger.log
具有以下内容:
Started classA
Initiated Script
Looping
Into method run
Looping
Into method run
...
有任何线索吗?
推荐答案
原因是当您进行logging.getLogger()时,类和脚本具有相同的记录器对象.这是一个单身人士.如果您想要其他记录器,则应传递记录器名称,例如logging.getLogger('logger1')
通常,库会执行logging.getLogger(__name__)
,以便每个模块都使用不同的记录器.请参考 http://docs.python.org/2/library/logging. html#logger-objects
The reason is the class and script have the same logger object when you do logging.getLogger(). It's a singleton. If you want different loggers then you should pass the logger name e.g logging.getLogger('logger1')
Typically libraries do logging.getLogger(__name__)
so that each module gets a different logger. refer http://docs.python.org/2/library/logging.html#logger-objects
我已经修改了您的代码,以便现在可以正常使用
I have modified your code so that it works as expected now
import logging, logging.handlers
from logging.handlers import TimedRotatingFileHandler
class Logger(object):
def __init__(self, log_filename, name):
logging.basicConfig(format='%(asctime)s %(message)s')
formatter = logging.Formatter('%(asctime)s - %(levelname)s - %(message)s')
loghandler = TimedRotatingFileHandler(
log_filename, when="midnight", backupCount=50
)
loghandler.setFormatter(formatter)
self.logger = logging.getLogger(name)
self.logger.setLevel(logging.INFO)
self.logger.addHandler(loghandler)
def getLogger(self):
return self.logger
class ClassA(object):
def __init__(self):
log = Logger(log_filename='class_logger.log', name="Class")
self.logger = log.getLogger()
self.logger.info('Started ClassA')
def run(self):
self.logger.info('Into method run')
A = ClassA()
log = Logger(log_filename='script_logger.log', name="Script")
logger = log.getLogger()
logger.info('Initiated Script')
for x in range(5):
logger.info('Looping')
A.run()
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