C#调试日志控制台应用程序 [英] C# debug log console app

问题描述

我正在尝试创建一个控制台窗口以使用C#进行调试.

I am trying to create a console window for debugging in C#.

例如，请考虑以下情形:

我有一个表单应用程序，我想将事件实时记录到控制台窗口.
触发事件后，表单应用程序应将要打印的数据发送到控制台应用程序，以便我可以看到事件何时被触发以及有关特定事件的数据.
当我在控制台应用程序中输入特定命令时，它将命令发送到表单应用程序并触发事件.

For example, consider the following scenario:

I have a forms app and I want to log events to a console window in real time.
When an event is triggered the forms app should send data to be printed to the console app so that I can see when the event is triggered and data about the specific event.
When I input a specific command in the console app, it sends the command to the forms app and triggers the event.

因为它是用于调试的，所以控制台应该是一个单独的应用程序，这样，如果主应用程序死了，控制台窗口就不会.

Because it is for debugging, the console should be a separate app so that if the main app dies, the console window won't.

如果我做对了，我认为我应该能够使Console应用程序与诸如Console2/Conemu之类的程序一起工作.

If I do this right I assume I should be able to get the console app working with programs such as Console2/Conemu.

有人知道实现这一目标的正确方法吗?

Does anyone know the correct technique to achieve this?

推荐答案

这些方法取决于您要如何初始化进程之间的通信.我相信，命名管道-是最佳选择.但是，如您所愿...

Thee ways, I think, depending how do you want to initialize communication between your processes. I believe, named pipes - is the best choice. But as you wish...

1)您可以使用以下命令创建"控制台

1) You may "create" your console with following command

ConEmuC.exe /ATTACH /ROOT "<Full path to your console\part.exe>" <Arguments console part>
or
ConEmu.exe /cmd "<Full path to your console\part.exe>" <Arguments console part>

2)附加"是从通常启动的控制台部件应用程序创建的控制台.阅读此处.这个想法是在刚刚创建的免费控制台中运行以下命令.

2) "Attach" created console from normally started console part application. Read here. The idea is to run following command in the free, just created console.

ConEmuC.exe /AUTOATTACH

3)最后，您可以尝试使用默认终端"功能.在此处中进行描述.

3) At last, you may try "Default Terminal" feature. Described here.

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