如何计算新登录的SID? [英] How to calculate the SID for new logins?

问题描述

我想在两个sql服务器实例上创建许多数据库用户.为了能够轻松地将数据库从一个实例复制到另一个实例，我希望SID保持一致.

I want to create a number of database users on two sql server instances. To be able to easily copy databases from one instance to another, I want the SIDs to be consistent.

我的想法是使用可预测的SID，以最大程度地减少维护麻烦.我梦到这样的事情:

My idea was to use predictable SIDs, to minimize maintenance pain. I a dreaming about something like this:

CREATE LOGIN newuser1 WITH PASSWORD = '...', SID = CAST('newuser1' AS BINARY(16))

-- or alternatively:
CREATE LOGIN newuser1 WITH PASSWORD = '...', SID = HASHBYTES('newuser1')

但是，CREATE LOGIN命令似乎不支持计算SID的值:

Calculating values for the SID, however, seems not to be supported by the CREATE LOGIN command:

Meldung 102, Ebene 15, Status 1, Zeile 1
Falsche Syntax in der Nähe von "SID". -- Wrong syntax near "SID"

如何为SID使用计算值?

推荐答案

这可以通过将sql语句组装到变量中并用sp_executesql执行它来实现:

This can be accomplished by assembling the sql statement in a variable and the executing it with sp_executesql:

DECLARE @SQL nvarchar(4000)

SET @SQL = 'CREATE LOGIN newuser1 WITH PASSWORD = ''...'', SID = 0x'+CONVERT(VARCHAR(1000), CAST('newuser1' AS binary(16)), 2)
PRINT @SQL
EXEC sp_executesql @SQL

或者，如果您想重用这种方法，则可以使用创建存储过程:

Alternatively, if you want to reuse this approach, you can use create a stored procedure:

CREATE PROCEDURE create_user_with_predictable_sid
    @UserName varchar(256),
    @Password varchar(256)
AS
DECLARE @SQL nvarchar(4000) = 'CREATE LOGIN '+@UserName+' WITH PASSWORD = '''+@Password+''', SID = 0x'+CONVERT(VARCHAR(1000), CAST(@UserName AS binary(16)), 2)
PRINT @SQL
EXEC sp_executesql @SQL
GO  

GO

create_user_with_predictable_sid 'newuser1', '...'
GO

DROP PROCEDURE create_user_with_predictable_sid

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