如何将长整数时间转换为NSString或NSDate以显示时间? [英] How to convert long-integer time to NSString or NSDate to display time?

问题描述

我从Java Date获得了一个序列号，该序列号转换为长整数，例如"1352101337000". 我遇到的问题是如何将这个长整数解析为NSDate或NSString，以便我可以清楚地知道序列号显示的时间.

I got a serial number form Java Date which convert into long-integer such as "1352101337000". The problem I met is how to analyze this long-integer number back to NSDate or NSString so that I can clear to know what time the serial number is displaying.

有人对此案有解决方案吗?

Do anybody have solution for this case?

推荐答案

使用此

NSTimeInterval timeInMiliseconds = [[NSDate date] timeIntervalSince1970];

要改回它，

NSDate* date = [NSDate dateWithTimeIntervalSince1970:timeInMiliseconds];

根据 Apple文档 ，

NSTimeInterval:用于指定时间间隔，以秒为单位.

NSTimeInterval: Used to specify a time interval, in seconds.

typedef double NSTimeInterval;

它是double类型的.

It is of type double.

要将日期转换为字符串，

To convert a date to string,

NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
[formatter setDateFormat:@"yyyy-MM-dd HH:mm:ss zzz"];

//Optionally for time zone converstions
[formatter setTimeZone:[NSTimeZone timeZoneWithName:@"..."]];

NSString *stringFromDate = [formatter stringFromDate:myNSDateInstance];

[formatter release];

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