多头按位操作 [英] Bitwise operation on longs

问题描述

我尝试编译此代码:

Int64 itag = BitConverter.ToInt64(temp, 0);
itag &= 0xFFFFFFFFFFFFFC00;

但是，这给了我以下错误:

However this gives me the following error:

运算符'& ='不能应用于类型为'long'和'ulong'的操作数

Operator '&=' cannot be applied to operands of type 'long' and 'ulong'

我该怎么做?

推荐答案

请参见

如果文字没有后缀，则具有可以表示其值的以下第一种类型:int，uint，long，ulong.

您有

0xFFFFFFFFFFFFFC00

但是Int64.Max是:

but Int64.Max is:

0x7FFFFFFFFFFFFFFF

所以long不够大，并且ulong被当作文字的类型.

so long is not big enough and ulong is taken as the type of the literal.

现在您在左侧有带符号的Int64，在右侧有ulong，但是，没有&=重载，接受了该组合，这会导致错误

Now you have on the left side a Int64, which is signed, and on the right side you have ulong, however, there is not overload of &= which accepts that combination, which leads to the error.

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