创建“马里奥风格金字塔". [英] Creating a "Mario Style Pyramid"

问题描述

我正在学习哈佛CS50在线课程，问题之一是使用空格和哈希值创建马里奥风格金字塔".我已经解决了空间，但是散列给我带来了麻烦.这是代码:

I'm going through the Harvard CS50 online course and one of the problems is to create a "mario style pyramid" using spaces and hashes. I've got the spaces solved but the hashes are giving me trouble. Here's the code:

#include <stdio.h>
#include <cs50.h>

int main(void)
{
    //get height between 1 and 23
    int height;
    do
    {
        printf("Please enter a height: ");
        height = GetInt();
    }
    while (height < 1 || height > 23);

    //build pyramid
    for (int i = 0; i < height ; i++)
    {
        //add spaces
        for (int space = height - 1 - i; space >= 0; space--)
            printf(" ");

        //add hashtags
        for (int hash = 2 + i; hash <= height; hash++)
            printf("#");

        printf("\n");
    }
}

当我在高度为5的终端中运行它时，我会得到这个信息:

When i run it in the terminal with a height of 5 i'm getting this:

     ####
    ###
   ##
  #
   <-- space here also

当我想要这个时:

    ##
   ###
  ####
 #####
######

任何反馈将不胜感激，谢谢

Any feedback would be appreciated, thanks

推荐答案

只需尝试以下代码:

int main(void)
{
    int height;
    printf("Please enter a height: ");
    scanf("%d", &height);

    //build pyramid
    for (int i = height; i >= 1; i--)
    {
        //add spaces
        for (int space = 1; space < i; space++)
            printf(" ");

        //add hashtags
        for (int hash = height; hash >= i-1; hash--)
            printf("#");

        printf("\n");
    }
}

height的值为 5 时，您将获得所需的输出:

when the value of height is 5, you get the desired output:

    ##
   ###
  ####
 #####
######

请参见 工作小提琴 .

See the Working Fiddle.

在您的代码中，当i的值为 0 时:

In your code, when the value of i is 0 in:

for (int i = 0; i < height ; i++)
         ^^^^^^

其他循环执行如下:

for (int space = height - 1 - i; space >= 0; space--)
    printf(" ");

在这里，循环初始化 space = 4 (当height为 5 时)，循环条件一直有效到space >= 0，因此它将打印前4个字符为" ".

here, the loop initializes space = 4 (when height is 5) and the loop condition is valid till space >= 0, so it prints the first 4 characters as " ".

最后，涉及到此循环:

for (int hash = 2 + i; hash <= height; hash++)
    printf("#");

在这里，循环初始化 hash = 2 (i在第一个循环中为 0 ，还记得吗?)条件持续到hash <= height.因此，由于上述条件在以下条件中计算为 2,3,4,5 ，因此它将下一个4个字符打印为"#":

here, the loop initializes hash = 2 (i was 0 in the first loop, remember that?) and the loop conditions continues till hash <= height. So, it prints the next 4 characters as "#" as the above condition evaluates to 2,3,4,5 in:

(int hash = 2; hash <= 5; hash++)
           ^^^        ^^^

其余代码继续进行并产生如下输出:

and the rest of the code carries on and produces the output as:

     ####
    ###
   ##
  #

如果您能够理解上述逻辑，那么您也可以解码我的解决方案:)

If you are able to understand the above logic, then you'd be able to decode my solution as well :)

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