程序模拟带有偏向硬币的抛硬币 [英] Program that simulates a coin toss with a bias coin
问题描述
我没有任何代码,主要是因为我还没有开始处理这个特定问题.这是我的C编程课的功课.
I don't have any code, mainly because I haven't started working on this particular problem. It is for homework for my C Programming class.
我的教授希望我们创建一个程序,将一个硬币(正面或反面)抛掷10,000次.但是,heads元素有55%的机会发生.我们必须使用具有用户提供的seed
值的随机数生成器.
My professor wants us to create a program that tosses a coin (heads or tails) 10,000 times. However, the heads element has a 55% chance to occur. We have to use a random number generator with a user-supplied seed
value.
从概念上讲,我知道该如何处理;编码方面,我一无所知.我知道如何制作抛硬币程序,但是没有偏见.
Conceptually, I know how to approach this; coding-wise, I have no clue. I know how to make a coin tossing program, but not with a bias.
我们将不胜感激.
我已经为我的硬币投掷程序附加了代码.我原本打算以此为基础来创建这个新的 bias 投币程序.
I've attached code for my coin tosser program. I had intended to use this as a basis for this new bias coin tossing program.
// CoinTosser_Homework4.cpp : Coin tossing program
// nxt3
#include "stdafx.h"
#include <stdio.h>
#include <stdlib.h>
#define HEADS 0
#define TAILS 1
int rand_int(int a, int b) {
return rand() % ((b - a + 1) + a);
}
int main() {
int tosses = 0, min = 0, heads = 0, tails = 0; //init tosses and number of user defined tosses
/*users input for number of tosses*/
printf("Enter number of coin tosses: ");
scanf("%i", &min);
while (tosses < min) {
tosses++;
if (rand_int(HEADS, TAILS) == HEADS)
heads++;
else
tails++;
}
//prints results of tosses
printf("Number of heads: %i\n", heads);
printf("Number of tails: %i\n", tails);
return 0;
}
推荐答案
以老式的方式进行操作:
Do it the old fashioned way:
rand() % 100 + 1;
为您提供1到100(含)范围内的数字.如果该数字小于或等于55,则为首.
gives you a number in the range 1 to 100 (inclusive). It's heads if that number is less than or equal to 55.
但是请注意,除非生成器的周期是100的倍数(可能不是)的倍数,否则此生成器是有偏差的.您应该真的要做的是使用类似
But note that this generator is biased unless the periodicity of the generator is a multiple of 100 (which is probably isn't). What you should really do is use something like
(int)(100.0 * rand() / (RAND_MAX + 1.0)) + 1
100.0
还规避了整数除法.
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