如何从另一个变量名创建变量? [英] how do i create a variable from another variable name?

问题描述

好吧...在php中我该怎么做?给出以下情况:

ok...in php how do i do this? given the following scenario:

// array of letters
var $letters = array('a', 'b', 'c');
// loop through array and create empty arrays with names like $a, $b, $c
foreach($letters as $letter) {
    var $$letter = array();
}

推荐答案

您的代码几乎正确.您只需要删除第二行和第五行的"var"即可.

Your code was almost correct. You just need to remove 'var' on the 2nd and fifth lines.

// array of letters
$letters = array('a', 'b', 'c');
// loop through array and create empty arrays with names like $a, $b, $c
foreach($letters as $letter) {
    $$letter = array();
}

这正常工作(如您所述).我测试过了.

This works correctly (as you described). I tested it.

更多此处有关变量的信息.

顺便说一句，我建议您不要在PHP中使用eval().

这篇关于如何从另一个变量名创建变量?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！