Linux Shell脚本中的while循环超时 [英] Timeouting a while loop in Linux shell script

问题描述

这很好(无限循环):

$ while TRUE; do printf ".";done

............................................... .....................

.............................................................................

我正在尝试使用timeout命令超时此while loop. 所有这些都不起作用:

I am trying to timeout this while loop with the timeout command. All these don't work:

$ timeout 5 while TRUE; do printf ".";done
$ timeout 5 "while TRUE; do printf ".";done"
$ timeout 5 "while TRUE; do printf \".\";done"
$ timeout 5 $(while TRUE; do printf ".";done)
$ timeout 5 $('while TRUE; do printf ".";done')

正确的方法是什么(如果存在)?

What is the correct way (if it exists)?

推荐答案

我认为，解决您的问题的方法是执行另一个Shell实例并将适当的命令传递给它. 根据bash手册:

I think that the solution to your problem is to execute another shell instance and pass proper commands to it. According to bash manual:

-c        If the -c option is present, then commands are read from the first non-option argument command_string.

因此，我的解决方案将是这样的:

Thus my solution would be something like that:

timeout 5 bash -c -- 'while true; do printf ".";done'

--确保将以下参数视为非选项.而''有助于通过"而不造成不必要的转义

-- assures that the following arguments will be treated as non-option. And '' helps with passing " without unnecessary escaping

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