使用8位无符号整数变量作为计数器循环遍历256个值 [英] Loop over 256 values using 8-bit unsigned integer variable as counter
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问题描述
所以我只是想用连续数字0-255填充缓冲区.我对此没多想,最终陷入了无限循环.
So I was just trying to fill a buffer with consecutive numbers 0-255. I didn't think much on it and ended up in an infinite loop.
uint8_t i;
uint8_t txbuf[256];
for (i=0; i<256; i++) {
txbuf[i] = i;
}
问题在于,i
永远不会是256,因为它在255之后会翻转为零.
the problem being that i
will never be 256 as it rolls over to zero after 255.
我的问题是,有没有办法在不将i
增大到16位值的情况下执行此循环?
my question is, is there a way to do this loop without bumping i
up to a 16 bit value?
注意:我知道我可以将循环更改为i<255
并为最终位置添加另一行,但是我试图找出一种更好的方法.
Note: I know I could change the loop to i<255
and add another line for the final spot but I'm trying to figure out of there is a nicer looking way.
推荐答案
uint8_t txbuf[256];
uint8_t i = 0;
do {
txbuf[i] = i;
} while (i++ != 255);
或
uint8_t txbuf[256];
uint8_t i = 255;
do {
txbuf[i] = i;
} while (i--);
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