基于最大后继零在逗号后删除零 [英] Removing zeros after comma based on maximum consequent zeros

问题描述

我有一个带有网格的页面，其中保存了用户号码.它具有以下模式-每个数字以逗号后的3位数字结尾.看起来不太好，例如当用户的输入是

I have a page with a grid where user's numbers get saved. It has a following pattern - every number ends with 3 digits after comma. It doesn't look nice, when for example user's input is

123,450
123,670
123,890

最好在逗号后再加上2个数字，因为最后一个0绝对毫无意义且多余.

It's much better to have just 2 numbers after comma, because last 0 is absolutely meaningless and redundant.

仅当数组中的至少一个元素不以0

The way it still should have 3 digits is only if at least one element in an array doesn't end up with 0

例如:

123,455
123,450
123,560

在这种情况下，数组的第一个元素的最后一位不等于0，因此所有元素都应具有3位.带有2个或1个零的相同故事

In this case 1st element of the array has the last digit not equal to 0 and hence all the elements should have 3 digits. The same story with 2 or 1 zeros

零是多余的:

123,30
123,40
123,50

零是必要的

123,35
123,40
123,50

问题是如何以编程方式实现它?我是这样开始的:

The question is how can I implement it programatically? I've started like this:

var zeros2Remove = 0;
numInArray.forEach(function(item, index, numInArray) 
{
    var threeDigitsAfterComma = item.substring(item.indexOf(',') + 1);

    for(var j = 2; j <= 0; j--) 
    {
        if(threeDigitsAfterComma[j] == 0) 
        {
            zeros2Remove =+ 1;
        } 
        else //have no idea what to do..
    }   
})

在我的实现中，我不知道该怎么做，因为我必须遍历每个元素，但是如果至少一个数字的最后一位等于零，则将其中断.外循环，但不知道如何，而且我绝对确定我不必...

Well in my implementation I don't know how to do it since I have to iterate through every element but break it if at least 1 number has a last digit equal to zero.. In order to do that I have to break outer loop, but don't know how and I'm absolutely sure that I don't have to...

推荐答案

我认为以下代码正是您要寻找的代码，请操纵数字并查看更改:

I think the following code what you are looking for exactly , please manipulate numbers and see the changes :

var arr = ["111.3030", "2232.0022", "3.001000", "4","558.0200","55.00003000000"];
var map = arr.map(function(a) {
  if (a % 1 === 0) {
    var res = "1";
  } else {
    var lastNumman = a.toString().split('').pop();
    if (lastNumman == 0) {
      var m = parseFloat(a);
      var res = (m + "").split(".")[1].length;
    } else {
      var m = a.split(".")[1].length;
      var res = m;
    }
  }

  return res;

})
var maxNum = map.reduce(function(a, b) {
  return Math.max(a, b);
});

arr.forEach(function(el) {
  console.log(Number.parseFloat(el).toFixed(maxNum));
});

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