将脚本应用于子文件夹并相应地命名结果的循环--R [英] loop for applying script to sub-folders and name results accordingly --R

问题描述

我有一个脚本来针对一个文件夹中的任何现有火车.csv文件获取test-results.csv文件的corssproduct

I have a script to get corssproduct of test-results.csv file against any exsiting train .csv file in one folder

已编辑-添加了一些更正

Edited -- some corrections added

mytest <- function(data) {
data01 <- as.matrix(read.csv(file = "test/test-results.csv", sep = ",", header=FALSE))
data02 <- as.matrix(read.csv(file = data, sep = ",", header=FALSE))
test <- list()
test01<- list()
test02<- list()
i<- 1
while (i <= 25){
    test01[[i]] <- c(data01[i,  ])
    test02[[i]] <- c(data02[i,  ])
    test[[i]]<- crossprod(test01[[i]],test02[[i]])
    i <- i+1
}
return(mytest)
}
result <- lapply(list.files(pattern='^tain.*\\.csv', recursive=TRUE, full.names = TRUE),test)
for (i in seq(length(result))) {
 write.csv(do.call(cbind,result),'result.csv', row.names = FALSE) 
}

我有几个结构相同的文件夹

I have few folders with same structure

Main|experiment 01|test|test-results.csv, train01.csv, train02.csv, train03.csv
Main|experiment 02|test|test-results.csv, train01.csv, train02.csv

我现在想创建一个脚本，以便将相同的脚本应用于所有这些文件夹并返回结果(例如results-experiment01.csv)，而不是将它们应用100次

I now want to create a script if possible to apply the same script to all of those folders and return the results (e.g. results-experiment01.csv) instead of applying them 100 times

抱歉，这看起来很可怕... R中的新功能

sorry if this looks horrible ... new in R

推荐答案

如果仅使用dir或list.files进行调用，您会得到一个文件列表作为字符向量(例如下面的示例中的dirlist )

lets say with just plain dir or list.files call with recursive = TRUE you get a file list as character vector (like dirlist in example below)

> dirlist
[1] "Main/experiment 01/test/a.csv"  "Main/experiment 02/test/b.csv"  "Main/experiment 02/test/d.txt"  "Main/experiment 02/dummy/a.csv"
[5] "temp1.csv"                      "Main/temp2.csv"  

您可以使用以下正则表达式对该向量进行子集

You can subset this vector using regular expressions as follows

> csvfiles <- dirlist[grepl('.*(experiment [0-9]+)/test/.*\\.csv', dirlist)]
> csvfiles
[1] "Main/experiment 01/test/a.csv" "Main/experiment 02/test/b.csv"

然后，您可以再次使用正则表达式来获得结果名称.

Then you can get result names using regex again on this.

> resultsnames <-  paste('result_', gsub('.*(experiment [0-9]+)/test/.*\\.csv','\\1', csvfiles), sep="")
> resultsnames
[1] "result_experiment 01" "result_experiment 02"

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