R中的一个因数循环 [英] Looping with A Factor in R

问题描述

因此，此代码根据因子bonegrp的值填充向量Bone的值.我想以更简洁的方式完成此操作.

So this code fills in the values of the vector Bone according to the value of the factor bonegrp. I would like to accomplish this in a more concise manner.

谢谢！

v <- dat$bonegrp=="Bone2"  
Bone[v] <- "Gast 1"  
v <- dat$Bonegrp=="Bone3"  
Bone[v] <- "Gast 2"  
v <- dat$Bonegrp=="Bone4"  
Bone[v] <- "Vert1"  
v <- dat$Bonegrp=="Bone5"  
Bone[v] <- "Vert2"  
v <- dat$Bonegrp=="Bone6"  
Bone[v] <- "Femur"  
v <- dat$Bonegrp=="Bone7"  
Bone[v] <- "Tibia"  
v <- dat$Bonegrp=="Bone8"   
Bone[v] <- "Meta."  
v <- dat$Bonegrp=="Bone9"  
Bone[v] <- "Phal."  
v <- dat$Bonegrp=="Bone10"  
Bone[v] <- "PCau."  
v <- dat$Bonegrp=="Bone11"  
Bone[v] <- "MCau."  
v <- dat$Bonegrp=="Bone12"  
Bone[v] <- "DCau.  

推荐答案

如果Bonegrp中只有12个级别，那么您可以查看是否可行(根据有关数据结构的其他信息进行编辑):

If there are only 12 levels in Bonegrp then you could see if this works (edited per additional info regarding data structure):

Bone <- c(NA, "Gast 1", "Gast 2", "Vert1", "Vert2", "Femur","Tibia", "Meta.", 
          "Phal.", "PCau.", "MCau.", "DCau.")[as.numeric(dat$Bonegrp)]

它基本上是使用向量，并根据Bonegrp的数值等效项查找适当的字符串.您真的应该提供有关数据的更多信息.仅仅提供代码通常是不够的.

It is basically using a vector and looking up the proper string based on the numeric equivalent of Bonegrp. You really should provide more information about your data. Just provided code is often not enough.

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