显示所有行并通过提交更新所有行 [英] Display all rows and update all rows by a submit
问题描述
我想通过php查询显示所有行,并通过sql中的提交按钮更新所有行.我可以通过以下方式通过自己的提交按钮显示所有行并更新特定行.但是我想通过一个提交按钮来全部更新.
I want to display all rows by a php query and update all by a submit button in sql. I this way below a can display all row and update particular row by its own submit button. But I want to update all by a single submit button.
为此,我非常感谢,我想循环进行更新.但在这种情况下,我不明白该怎么做.
So for do it, I thank, I want to loop for update. But I cannot understand how to do it in this case.
这是我的代码:
<?php
include_once('../db.php');
global $db;
$result = mysqli_query($dbh,"SELECT * FROM ppad");
if(!$result) {
die("Database query failed: " . mysqli_error());
}
while($row = mysqli_fetch_assoc($result)) {
$id=$row['id'];
$name=$row['name'];
$date=$row['date'];
$title=$row['title'];
$Detail=$row['Detail'];
echo '<form action="padSproccess.php" method="POST">
<table width="100%" border="1">
<tr>
<td width="10%">Date</td>
<td width="14%">Time</td>
<td width="20%">Name(url)</td>
<td width="30%">Detail</td>
</tr>
<tr>
<td width="10%"><input type="text" name="date" maxlength="2" value="'.$date.'"></td>
<td width="14%"><input type="text" name="title" maxlength="50" value="'.$title.'"></td>
<td width="20%"><input type="text" name="name" maxlength="50" value="'.$name.'"></td>
<td width="30%"><input type="text" name="Detail" maxlength="100" value="'.$Detail.'"></td>
<input type="hidden" name="id" value="'.$id.'">
</tr>
</table>
<input type="submit" name="submit" id="submit" value="Submit">
</form>';}
?>
padSproccess.php
include("../db.php");
global $db;
if(isset($_POST['submit'])){
$date = mysqli_real_escape_string($dbh,$_POST['date']);
$title = mysqli_real_escape_string($dbh,$_POST['title']);
$name = mysqli_real_escape_string($dbh,$_POST['name']);
$Detail = mysqli_real_escape_string($dbh,$_POST['Detail']);
$id = mysqli_real_escape_string($dbh,$_POST['id']);
// update data in mysql database
$update = mysqli_query($dbh,"UPDATE ppad SET date='$date', month='$month', name='$name', Detail='$Detail' WHERE id = '$id'");
// if successfully updated.
}
推荐答案
您首先需要准备的是一个总体表单,而不是每个表单都有一个表单(除非您想使用JavaScript来触发Ajax调用).因此,您需要做的是确保每一行都可以与一个特定的ID相关联:
What you need to do first is have an overall form, not a form for each (unless you want to throw in javascript to fire off ajax calls). So what you'll need to do is make sure each row can be associated with a specific id:
<?php
include_once '../db.php';
$result = mysqli_query($dbh, "SELECT * FROM ppad");
if(!$result) {
die("Database query failed: " . mysqli_error());
}
?>
<form action="padSproccess.php" method="POST">
<table width="100%" border="1">
<thead>
<tr>
<td width="10%">Date</td>
<td width="14%">Time</td>
<td width="20%">Name(url)</td>
<td width="30%">Detail</td>
</tr>
</thead>
<tbody>
<?php
while($row = mysqli_fetch_assoc($result)) {
$id = $row['id'];
$name = $row['name'];
$date = $row['date'];
$title = $row['title'];
$Detail = $row['Detail'];
echo '
<tr>
<td width="10%"><input type="text" name="date[' . $id . ']" maxlength="2" value="'.$date.'"></td>
<td width="14%"><input type="text" name="title[' . $id . ']" maxlength="50" value="'.$title.'"></td>
<td width="20%"><input type="text" name="name[' . $id . ']" maxlength="50" value="'.$name.'"></td>
<td width="30%"><input type="text" name="Detail[' . $id . ']" maxlength="100" value="'.$Detail.'"></td>
</tr>
';
}
?>
</tbody>
</table>
<input type="submit" name="submit" id="submit" value="Submit">
</form>
然后在padSproccess.php
中,您将收到一个names
,dates
,titles
和Details
的数组,每个数组均由该行的ID
键.这样就变成了这样的东西:
Then in padSproccess.php
you'll receive an array of names
, dates
, titles
and Details
, each one keyed by the ID
of the row. So that'll change to something like this:
<?php
include "../db.php";
if(isset($_POST['submit'])){
$ids = array_keys($_POST['name']);
foreach ($ids as $id) {
$date = mysqli_real_escape_string($dbh,$_POST['date'][$id]);
$title = mysqli_real_escape_string($dbh,$_POST['title'][$id]);
$name = mysqli_real_escape_string($dbh,$_POST['name'][$id]);
$Detail = mysqli_real_escape_string($dbh,$_POST['Detail'][$id]);
$id = mysqli_real_escape_string($id);
// update data in mysql database
$update = mysqli_query($dbh,"UPDATE ppad SET date='$date', month='$month', name='$name', Detail='$Detail' WHERE id = '$id'");
}
// if successfully updated.
}
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