在bash中循环行命令 [英] Loop a line command in bash

问题描述

我将如何循环此行以将所有jpg文件都打印到文本文件中?

How would I loop this line to print everything jpg to a text file??

stat --printf="%s" *.jpg >> results.txt

您还将如何根据文件大小打印result.txt?代码看起来如何?文件的确切大小为40318

How would you also be able to print results.txt based on a file size?? How would the code look?? The exact size of the file is 40318

推荐答案

您已经在打印所有* .jpg文件的结果.唯一的问题是，通过使用--printf="%s"，您正在更改stat的输出格式以仅打印尺寸(每行之间没有换行符或空格).

You already are printing the results for all *.jpg files. The only problem is that by using --printf="%s" you are changing the output format of stat to print only the size (without line breaks or spaces in between each item).

请尝试:

stat --printf="%s\n" *.jpg >> results.txt
#  OR
stat -c "%s" *.jpg >> results.txt

要在文件大小旁边打印文件名，请尝试:

To print the filename next to the size, try:

stat --printf="%n %s\n" *.jpg >> results.txt
# OR
stat -c "%n %s" *.jpg >> results.txt

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