io.popen-如何在Lua中等待进程完成? [英] io.popen - how to wait for process to finish in Lua?

问题描述

我必须在Lua中使用io.popen来运行带有命令行参数的可执行文件. 如何等待Lua中的进程完成，以便可以捕获预期的输出?

I have to use io.popen in Lua to run an executable which takes a command line argument. How to wait for a process to finish in the Lua so that expected output can be captured?

  local command = "C:\Program Files\XYZ.exe /all"

  hOutput = io.popen(command)
  print(string.format(""%s", hOutput))

假定可执行文件是XYZ.exe，需要使用命令行参数/all进行调用.

Suppose the executable is XYZ.exe which needs to be called with command line argument /all.

一旦执行io.popen(command)，该过程将返回一些需要打印的字符串.

Once io.popen(command) gets executed, the process will return some string which needs to be printed.

我的代码段:

function capture(cmd, raw)
  local f = assert(io.popen(cmd, 'r'))
  -- wait(10000); 
  local s = assert(f:read('*a')) 
  Print(string.format("String: %s",s )) 
  f:close() 
  if raw then return s end 
  s = string.gsub(s, '^%s+', '') 
  s = string.gsub(s, '%s+$', '') 
  s = string.gsub(s, '[\n\r]+', ' ') 
  return s 
end 
local command = capture("C:\Tester.exe /all")

您的帮助将不胜感激.

推荐答案

如果您使用的是标准Lua，则您的代码看起来有些奇怪.对于超时或平台依赖项的io.popen语义，我不是很确定，但是以下内容至少在我的机器上有效.

If you are using standard Lua your code looks a bit odd. I am not completely sure about io.popen semantics regarding timeouts or platform dependencies, but the following works at least on my machine.

local file = assert(io.popen('/bin/ls -la', 'r'))
local output = file:read('*all')
file:close()
print(output) -- > Prints the output of the command.

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