优化Lua以进行循环执行 [英] Optimizing Lua for cyclic execution

问题描述

我每个10毫秒的程序周期执行一次Lua脚本.使用相同的Lua_state(在我的应用中一次调用过luaL_newstate)

I'm exeucting my Lua script once per program cycle of 10 ms. using the same Lua_state (luaL_newstate called once in my app)

可以肯定的是，调用luaL_loadbuffer可以非常快速地编译脚本，但由于脚本不会更改，因此每次执行脚本时似乎都不需要这样做.

Calling luaL_loadbuffer complies the script very fast for sure, still it seems unneccessary to do this every time the script is executed since the script does not change.

试图使用lua_dump()保存二进制文件然后执行它，但是lua_pcall()由于某种原因不接受二进制文件.

Tried to save binary using lua_dump() and then execute it, but lua_pcall() didn't accept the binary for some reason.

关于如何优化的任何想法? (在这里，LuaJIT并不是一个永久的选择)

Any ideas on how to optimize? (LuaJIT is not an unfortenately an option here)

Jan

推荐答案

您是正确的，如果代码没有更改，则没有理由重新处理代码.也许您可以执行以下操作:

You're correct, if the code is not changing, there is no reason to reprocess the code. Perhaps you could do something like the following:

luaL_loadbuffer(state, buff, len, name); // TODO:  check return value
while (true) {
    // sleep 10ms
    lua_pushvalue(state, -1); // make another reference to the loaded chunk
    lua_call(state, 0, 0);
}

您会注意到，我们只是在堆栈顶部复制了函数引用，因为lua_call从堆栈中删除了它调用的函数.这样，您就不会丢失对已加载块的引用.

You'll note that we simply duplicate the function reference on the top of the stack, since lua_call removes the function that it calls from the stack. This way, you do not lose a reference to the loaded chunk.

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