如何从Lua中的字符串中删除空格? [英] How to remove spaces from a string in Lua?

问题描述

我想从Lua中的字符串中删除所有空格.这是我尝试过的:

I want to remove all spaces from a string in Lua. This is what I have tried:

string.gsub(str, "", "")
string.gsub(str, "% ", "")
string.gsub(str, "%s*", "")

这似乎不起作用.如何删除所有空格?

This does not seem to work. How can I remove all of the spaces?

推荐答案

它有效，您只需要分配实际结果/返回值即可.使用以下变体之一:

It works, you just have to assign the actual result/return value. Use one of the following variations:

str = str:gsub("%s+", "")
str = string.gsub(str, "%s+", "")

我使用%s+是因为替换空匹配毫无意义(即没有空格).这只是没有任何意义，所以我至少要寻找一个空格字符(使用+量词).

I use %s+ as there's no point in replacing an empty match (i.e. there's no space). This just doesn't make any sense, so I look for at least one space character (using the + quantifier).

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