LuaSocket服务器:accept()超时(TCP) [英] LuaSocket server:accept() timeout (TCP)

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问题描述

问题

跟随LuaSocket 引言我设法获得了服务器正在运行.我还设法从客户端连接.但是,我注意到服务器脚本冻结,直到server:accept()获得连接.

Following LuaSocket Introduction I managed to get the server running. I also managed to connect from the client side. I noticed, however, that the server script freezes until server:accept() gets the connection.

研究

LuaSocket 参考指定:

LuaSocket Reference specifies:

使用settimeout方法或accept可能会阻塞,直到另一个客户端出现为止.

Use the settimeout method or accept might block until another client shows up.

这甚至包含在示例代码中.但是,client:settimeout(10)local client = server:accept()之后被调用,因此脚本在到达这一点之前被阻塞.

This is even included in the example code. However, client:settimeout(10) is called after local client = server:accept() so the script gets blocked before it reaches this point.

我读到这可以通过多线程解决,但这似乎有点夸张.

I read that this could be worked around by multithreading but this seems to be an exaggeration.

问题

  1. 如何使服务器脚本停止等待连接并继续前进?
  2. 如何防止client:receive()(服务器端)和tcp:receive()(客户端)(或client:settimeout(10)负责)类似的问题?
  1. How do you cause the server script to stop waiting for connection and move on?
  2. How do I guard from similar problems with client:receive() (server side) and tcp:receive() (client side) (or client:settimeout(10) takes care of that)?

代码

服务器(来自LuaSocket 简介)

-- load namespace
local socket = require("socket")
-- create a TCP socket and bind it to the local host, at any port
local server = assert(socket.bind("*", 0))
-- find out which port the OS chose for us
local ip, port = server:getsockname()
-- print a message informing what's up
print("Please telnet to localhost on port " .. port)
print("After connecting, you have 10s to enter a line to be echoed")
-- loop forever waiting for clients
while 1 do
  -- wait for a connection from any client
  local client = server:accept()
  -- make sure we don't block waiting for this client's line
  client:settimeout(10)
  -- receive the line
  local line, err = client:receive()
  -- if there was no error, send it back to the client
  if not err then client:send(line .. "\n") end
  -- done with client, close the object
  client:close()
end

客户端(遵循此答案)

local host, port = "127.0.0.1", 100
local socket = require("socket")
local tcp = assert(socket.tcp())

tcp:connect(host, port);
--note the newline below
tcp:send("hello world\n");

while true do
    local s, status, partial = tcp:receive()
    print(s or partial)
    if status == "closed" then break end
end
tcp:close()

推荐答案

您应该可以使用

You should be able to use server:timeout() before calling server:accept():

server:settimeout(2)
local client, err = server:accept()
print(client, err)

如果2秒钟内没有请求,这将为我打印nil timeout.

This prints nil timeout for me if no request comes in 2 seconds.

这篇关于LuaSocket服务器:accept()超时(TCP)的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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