在lua中使用cURL [英] using cURL in lua

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本文介绍了在lua中使用cURL的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在尝试在一些lua脚本中使用curl库.

I am trying to use the curl library in a little lua script.

我知道有一个"-k"选项可禁用默认情况下curl进行的证书验证...但是我无法通过代码找到如何做到这一点.

I know there is a "-k" option to disable the certification verification that curl does by default... but I haven't been able to find how to do it via code.

这是我到目前为止的内容:

here's what I have so far:

  local cURL = require("cURL")

    headers = {"Accept: text/*",
               "Accept-Language: en",
               "Accept-Charset: iso-8859-1,*,utf-8",
               "Cache-Control: no-cache"}
    login_url = "https://10.10.2.1/cgi-bin/acd/myapp/controller/method?userid=tester&password=123123"

    c = cURL.easy_init()
    c:setopt_url(login_url)

    c:perform({writefunction=function(str)
                                succeed = succeed or (string.find(str, "srcId:%s+SignInAlertSupressor--"))
                             end }) 

感谢您的宝贵时间.

推荐答案

使用新版本的Lua-cURL [1],您可以编写

With new version of Lua-cURL[1] you can write

local cURL = require("cURL")

headers = {
  "Accept: text/*",
  "Accept-Language: en",
  "Accept-Charset: iso-8859-1,*,utf-8",
  "Cache-Control: no-cache"
}

login_url = "https://10.10.2.1/cgi-bin/acd/myapp/controller/method?userid=tester&password=123123"

c = cURL.easy{
  url            = login_url,
  ssl_verifypeer = false,
  ssl_verifyhost = false,
  httpheader     = headers,
  writefunction  = function(str)
    succeed = succeed or (string.find(str, "srcId:%s+SignInAlertSupressor--"))
  end
}

c:perform()

1- https://github.com/Lua-cURL/Lua-cURLv3

这篇关于在lua中使用cURL的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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