从C#将对象传递到Lua脚本 [英] Pass Object to Lua Script from C#

问题描述

我在C#中使用LuaInterface，并且一切设置正确.

I am using LuaInterface with C#, and have got everything set up correctly.

我想做的是，当使用lua.DoFile()启动脚本时，该脚本可以访问我可以发送的Player对象.

What I want to be able to do is that when the script is started using lua.DoFile(), that the script has access to a Player object that I can send...

当前代码:

public static void RunQuest(string LuaScriptPath, QPlayer Player)
{
    QMain.lua.DoFile(LuaScriptPath);
}

但是如您所见，脚本将无法访问Player对象.

But as you can see the script will not have access to the Player object.

推荐答案

我看到两个选项.第一个是使您的玩家成为Lua的全局变量:

I see two options. The first one is to make your player a global variable for Lua:

QMain.lua['player'] = Player

然后您就可以在脚本中访问player

Then you'll be able to access player in your script

第二个选项是让脚本定义一个接受播放器作为参数的函数.因此，如果您当前的脚本包含...code...，它将包含:

The second option is to have the script define a function accepting player as parameter. So if your current script contains ...code... now it will contain:

function RunQuest(player)
    ...code...
end

，您的C#代码将如下所示:

and your C# code will look something like this:

public static void RunQuest(string LuaScriptPath, QPlayer Player)
{
    QMain.lua.DoFile(LuaScriptPath); // this will not actually run anything, just define a function
    QMain.lua.GetFunction('RunQuest').Call(player);        
}

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