在Lua脚本中捕获并列出全局变量 [英] Capture and list Globals in Lua Script

问题描述

如何遍历整个脚本来捕获所有全局变量的列表.

How does one iterate thru an entire script capture a list of all globals.

我知道_G是环境表，它包含所有全局变量，但实际上包含所有全局变量.我只想要脚本中的全局变量

I understand that _G is the environment table and it holds all globals, but it hold literally ALL globals. I want the globals in my script only

推荐答案

除了_G本身是全局变量之外，_G是运行时表(因此只能在特定运行时的某个时刻列出) .没错，它将列出由脚本以及Lua状态初始化和使用的其他脚本设置的全局变量.

Other than _G being a global variable itself, _G is a runtime table (and so could only be listed at some point during a particular run). You're right that it would list globals that are set by the script as well as by the Lua state initialization and other scripts that are used.

找到编译器将作为全局变量绑定的变量标识符的一种方法是使用luac命令行工具:

One way to find the variable identifiers that the compiler would bind as globals is to use the luac commandline tool:

luac -l script.lua | grep [SG]ETGLOBAL

第二列给出行号.最后一列(注释)提供了标识符.

The second column gives the line number. The last column (comment) gives the identifier.

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