使用lubridate在R中添加/减去6个月(键合时间) [英] Add/subtract 6 months (bond time) in R using lubridate

问题描述

我希望使用lubridate可靠地增加和减少六个月.

I am looking to add and subtract six months reliably with lubridate.

例如，将12/31/2014加六个月应得出6/30/2015， 并添加到2/28/2014应该会导致8/31/2014

For example, adding six months to 12/31/2014 should result in 6/30/2015, and adding to 2/28/2014 should result in 8/31/2014

as.Date("2014-12-31") + months(6)的问题在于它会产生一个NA.另外，第二个结果是2014年8月28日，因为它不仅会在该月中添加6个月，然后知道该月的结束日期取决于该月.

The issue with as.Date("2014-12-31") + months(6), is that it yields an NA. Alternatively, the second result is 8/28/2014 because it doesn't just add 6 months to the month and then know where the day should end up dependent upon the month.

有什么方法可以快速纠正此问题?目前，我正在构建一个基本上使用开关并每月考虑的功能，但这很长，我也遇到了问题.

Is there any way to quickly correct this? At the moment, I am building a function to basically use a switch and consider each month, but this is very long and I am having problems with it as well.

谢谢！

推荐答案

lubridate函数%m+%在这里可能有用:

The lubridate function %m+% may be useful here:

在日期中添加和减去月份，但不超过新月份的最后一天

Add and subtract months to a date without exceeding the last day of the new month

as.Date("2014-12-31") %m+% months(6)
# [1] "2015-06-30"

要处理第二种情况，您需要使用ceiling_date舍入到最近的月份，并使用days减去一天.

To also handle the second case, you will need to round up to nearest month using ceiling_date, and subtract one day using days.

ceiling_date(as.Date("2014-02-28") %m+% months(6), unit = "month") - days(1)
# [1] "2014-08-31"

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