转换为日期并剥离时间? [英] convert to date and strip time?

问题描述

我有一些看起来像这样的数据:

I have some data that looks like this:

dates <- structure(c(1L, 2L, 4L, 3L), .Label = c("Sat, 18 Nov 2017 00:00:00 GMT", 
                                             "Thu, 16 Nov 2017 00:00:00 GMT", "Tue, 14 Nov 2017 00:00:00 GMT", 
                                             "Wed, 15 Nov 2017 00:00:00 GMT"), class = "factor")

我想将其转换为日期格式，而不是将其作为因素.此外，我想剥离格林尼治标准时间00:00:00，因为它毫无意义

I would like to convert it to a date format instead of having it as a factor. Additionally, I want to strip the 00:00:00 GMT because it is meaningless

我尝试了lubridate，但是格式出现问题:

I tried lubridate but I'm having troubles with the format:

library(lubridate)
mdy(dates)
Warning message:
All formats failed to parse. No formats found.

推荐答案

这似乎正在起作用:

as.POSIXct(dates, format = '%a, %d %b %Y %H:%M:%S')
#[1] "2017-11-18 GMT" "2017-11-16 GMT" "2017-11-15 GMT" "2017-11-14 GMT"

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