如何使用lxml从XML检索xsi:noNamespaceSchemaLocation? [英] How to retrieve xsi:noNamespaceSchemaLocation from XML with lxml?

问题描述

我正在尝试基于xsi:noNamespaceSchemaLocation验证XML.

I am trying to validate XML based on xsi:noNamespaceSchemaLocation.

我研究了这个问题，但似乎没有任何可用的解决方案.

I researched this question but it doesn't seem any available solutions for it.

我的XML文件如下:

<shiporder orderid="889923"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:noNamespaceSchemaLocation="shiporder.xsd">
  <orderperson>John Smith</orderperson>
  <shipto>
    <name>Ola Nordmann</name>
    <address>Langgt 23</address>
    <city>4000 Stavanger</city>
    <country>Norway</country>
  </shipto>
  <item>
    <title>Empire Burlesque</title>
    <note>Special Edition</note>
    <quantity>1</quantity>
    <price>10.90</price>
  </item>
  <item>
    <title>Hide your heart</title>
    <quantity>1</quantity>
    <price>9.90</price>
  </item>
</shiporder>

我从 w3school

这是我从根目录解析并获取attrib时得到的 {'{http://www.w3.org/2001/XMLSchema-instance}noNamespaceSchemaLocation': 'shiporder.xsd'}

This is what I get when parse and take attrib from root {'{http://www.w3.org/2001/XMLSchema-instance}noNamespaceSchemaLocation': 'shiporder.xsd'}

如何在Python中使用lxml做到这一点?我查看了其他解析器，但到目前为止还不知道该怎么做.

How can I do it with lxml in Python? I looked on other parsers but so far no idea how to do it.

推荐答案

感谢@mzjn指出了Clark表示法.

Thanks to @mzjn for pointing out about Clark notation.

我想出的解决方案是:

from lxml import etree

...

it = etree.fromstring(xml)
# We need to go through all keys since they can be in
# Clark notation and have URL with brackets as a prefix
for attr in it.attrib:
    if 'noNamespaceSchemaLocation' in attr:
        xsd = it.attrib.get(attr)
        break

...

# Do validations based on XSD URL value

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