获取网络客户端MAC地址，使用PhP的语法问题 [英] Getting Network Client MAC address, Syntax issue using PhP

问题描述

实际上，如果我直接在shell_exec()

Actually the below coding is working fine, if I provide the ip address directly inside the shell_exec()

$mac = shell_exec('arp -a 192.168.0.107'); 

如果，我从其系统获取客户端的ip并将其存储在变量中，然后调用该变量，如下所示，

If, I get the ip of the client from his system and stored in a variable and call the same, as given below,

$mac = shell_exec('arp -a' . escapeshellarg($ip));

输出未生成.

这是完整的代码:

<?php

$ip = $_SERVER['REMOTE_ADDR'];
$mac = shell_exec('arp -a'. escapeshellarg($ip));

//Working fine when sample client IP is provided...
//$mac = shell_exec('arp -a 192.168.0.107'); 

$findme = "Physical";
$pos = strpos($mac, $findme);
$macp = substr($mac,($pos+42),26);

if(empty($mac))
{
    die("No mac address for $ip not found");
}

// having it
echo "mac address for $ip: $macp";

?>

请告知，为什么escapeshellarg($ip)在shell_exec()中不起作用.

Please advise, why escapeshellarg($ip) does not work in the shell_exec().

推荐答案

shell_exec('arp '.$ip.' | awk \'{print $4}\'');

终端的结果

└──arp 10.1.10.26 | awk'{print $ 4}'

└── arp 10.1.10.26 | awk '{print $4}'

a4:5e:60:ee:29:19

这篇关于获取网络客户端MAC地址，使用PhP的语法问题的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！