Scapy ARP错误 [英] Scapy ARP mistake

问题描述

我在这里的代码应该说"ARP拥有("192.168.178.1/24")表示192.168.178.64， 但这对我不起作用. 上面写着有??的Ether/ARP". 这是代码:

my code right here is supposed to say "ARP who has ("192.168.178.1/24") says 192.168.178.64, but it does not work for me. It says "Ether/ARP who has ?? says ??" Here is the Code:

#!/usr/bin/python3

import scapy.all as scapy


def scan(ip):
    arp_request = scapy.ARP(pdst=ip)
    broadcast = scapy.Ether(dst="ff:ff:ff:ff:ff:ff")
    arp_request_broadcast = broadcast/arp_request
    print(arp_request_broadcast.summary())


scan("192.168.178.1/24")

推荐答案

该问题已解决.重试使用开发版本(在github上)

That was fixed. Retry using the development version (on github)

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