JSON为Android 2.2不工作 [英] Json for Android 2.2 not working

问题描述

我在我的应用我与仿真器和手机的Andorid 4.1和Android 2.2的测试。
在Android 4.2的一切工作正常还对仿真器的API 17。

但在2.2我得到错误：java.lang.ClassCastException：java.lang.String中

我没去调试，并在标有星行发生错误。

错误之前我也得到通知：在BufferedReader类的构造函数使用默认的缓冲区大小。是否需要8K-字符缓冲区这将是更好的是明确的。

任何帮助将是AP preciated。

 公共无效buildData（字符串jsonString，字符串code）{
    mProduct =新的HashMap＆LT;整数，产品＆GT;（）;
    尝试{
        ** JSONArray阵列=（JSONArray），其中新JSONTokener（jsonString）.nextValue（）; **
        的for（int i = 0; I＆LT; array.length（）;我++）{
            JSONObject的JSON = array.getJSONObject（I）
            如果（json.has（JSON_PRODUCT））{
                buildProduct（json.getString（JSON_PRODUCT），code）;
            }
            否则如果（json.has（JSON_NAME））{
                buildUser（json.getString（JSON_NAME））;
            }
        }
    }赶上（JSONException E）{
        // TODO自动生成catch块
        e.printStackTrace（）;
    }
}
 

我用这个code下载数据：

 字节公众[] getUrlBytes（字符串urlSpec）抛出IOException
    网址URL =新的URL（urlSpec）;
    HttpURLConnection的连接=（HttpURLConnection类）url.openConnection（）;    尝试{
        ByteArrayOutputStream出=新ByteArrayOutputStream（）;
        在的InputStream = connection.getInputStream（）;        如果（connection.getResponse code（）！= HttpURLConnection.HTTP_OK）
            返回null;        INT读取动作= 0;
        字节[]缓冲区=新的字节[1024];
        而（（读取动作= in.read（缓冲液））大于0）{
            out.write（缓冲液，0，读取动作）;
        }
        out.close（）;
        返回out.toByteArray（）;    } {最后
        connection.disconnect（）;
    }
}
 

我也应该追加例如jsonString那我送。

<$p$p><$c$c>{\"PRODUCT\":{\"0\":\"1\",\"product_id\":\"1\",\"1\":\"sdasd\",\"name\":\"sdasd\",\"2\":\"1\",\"person_id\":\"1\",\"3\":\"image\",\"image\":\"image\",\"4\":\"0\",\"alergen_id\":\"0\",\"5\":\"0\",\"contain\":\"0\",\"6\":\"-1\",\"aditiv_id\":\"-1\",\"7\":\"0\",\"tmpgrade\":\"0\"}}

解决方案

您尝试使用

  JSONArray阵列=新JSONArray（jsonString）;
 

或

 的JSONObject对象=新的JSONObject（jsonString）;
 

而不是使用

  Object对象=新JSONTokener（jsonString）.nextValue（）
 

I my application which I tested with emulator and phone Andorid 4.1 and Android 2.2. On Android 4.2 everything works ok also on emulator with API 17.

But on 2.2 I get error: java.lang.ClassCastException: java.lang.String

I did go debugging and the error occurs at line marked with stars.

Before error I also get notice: Default buffer size used in BufferedReader constructor. It would be better to be explicit if an 8k-char buffer is required.

Any help would be appreciated.

public void buildData(String jsonString, String code) {
    mProduct = new HashMap<Integer, Product>();
    try {
        **JSONArray array = (JSONArray) new JSONTokener(jsonString).nextValue();**
        for(int i = 0; i < array.length(); i++){
            JSONObject json = array.getJSONObject(i);
            if(json.has(JSON_PRODUCT)){
                buildProduct(json.getString(JSON_PRODUCT), code);
            }
            else if(json.has(JSON_NAME)){
                buildUser(json.getString(JSON_NAME));
            }
        }
    } catch (JSONException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
}

I use this code for downloading data:

public byte[] getUrlBytes(String urlSpec) throws IOException{
    URL url = new URL(urlSpec);
    HttpURLConnection connection = (HttpURLConnection)url.openConnection();

    try {
        ByteArrayOutputStream out = new ByteArrayOutputStream();
        InputStream in = connection.getInputStream();

        if(connection.getResponseCode() != HttpURLConnection.HTTP_OK)
            return null;

        int bytesRead = 0;
        byte[] buffer = new byte[1024];
        while((bytesRead = in.read(buffer)) > 0){
            out.write(buffer, 0, bytesRead);
        }
        out.close();
        return out.toByteArray();

    } finally {
        connection.disconnect();
    }
}

I should also append example of jsonString that I send.

{"PRODUCT":{"0":"1","product_id":"1","1":"sdasd","name":"sdasd","2":"1","person_id":"1","3":"image","image":"image","4":"0","alergen_id":"0","5":"0","contain":"0","6":"-1","aditiv_id":"-1","7":"0","tmpgrade":"0"}}

解决方案

You tried to use

JSONArray array = new JSONArray(jsonString);

or

JSONObject object = new JSONObject(jsonString);

instead of using

Object object = new JSONTokener(jsonString).nextValue()

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