正则表达式在Java手机号码验证 [英] regex for mobile number validation in java

问题描述

我想在工作中0的组合后的10位手机号码（或）0091 10位数的手机号码（或）folllowed +91其次是10位数字的电话号码。

I want to have phone number in working combination of '0' followed by 10 digit mobile number (or) 0091 folllowed by 10 digit mobile number (or) +91 followed by 10 digit number.

1）0遵循和+91 folowed号码与正则表达式如下工作我也想跟着0091号进行的工作，我的正则表达式是：

1) 0 followed and +91 folowed numbers are working with following regex i also want 0091 followed number to be worked, my regex is:

"^([0]|(?:[0][0]|\\+)(91))([7-9]{1})([0-9]{9})$";

您能告诉我一个工作正则表达式。

Could you suggest me working a regex.

推荐答案

您似乎打算（根据您到目前为止试过的）确切的正则表达式是：

The exact regex you seem to be going for (based on what you've tried so far) is:

^(?:0091|\\+91|0)[7-9][0-9]{9}$

• 0，+91或0091
开始

• 其次是7-9


• 后紧跟9个号码


• 无捕获组


• 必须匹配整个输入



工作RegExr 例如

作为一般的提示，已经制定了这一点，你自己我建议使用像 RegExr 或 RegexPal

As a general tip, to have worked this out yourself I'd advise using a site like RegExr or RegexPal

将其设置为多行模式（让 ^ 和 $ 比赛在每一行的结尾）再加入 0091 ， +91 和 0 到输入在单独的行盒 - 让您拥有这样的事情。

Set it to multi-line mode (so that ^ and $ match at the end of each line) then add 0091, +91 and 0 into the input box on separate lines - so you have something like this.

然后尽量使匹配只是一部分，你的情况，你需要像

Then try to make a regex that matches just that part, in your case you needed something like

^0091|\+91|0$

注意：在RegExr你没有逃跑反斜杠（所以当你在Java中使用正则表达式，你需要经过转义）

Note: on RegExr you don't have to escape backslashes (so when you use the regex in java you need to go through escaping them).

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