如何使用宏将字符串转换为变量名? [英] How to convert a string to variable name using macro?

问题描述

#define TRACE(arg1,...)  char* arg1; 

int main(void)
{
    int a=4;
    TRACE(("Hello",a));  // convert "Hello" to a valid char variable name.
    return 0;
}

在将字符串"Hello"转换为变量名时遇到麻烦. 例如:"Hello"应该通过使用宏转换为const char* Hello;.由于有双引号，我无法将其转换.这是我在堆栈溢出的第一个问题.

I'm having trouble in converting the string "Hello" into a variable name. for example: "Hello" should be converted as const char* Hello; by using a macro. Since there are double quotes I'm unable to convert it. This is my first question in Stack Overflow.

推荐答案

您不能在C语言中解串"字符串.

You can't "destringify" a string in C.

不过，您可以对令牌进行字符串化，因此解决方案是采用另一种方法:使用令牌hello并在需要"hello"时对其进行字符串化.

You can stringify a token, though, so the solution is to do it the other way around: use the token hello and stringify it when you need "hello".

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