从main()方法中获取可执行jar的名称 [英] Get name of executable jar from within main() method
问题描述
我创建了一个可执行jar,并使用commons-cli使用户能够在启动客户端时指定命令行参数.一切正常.但是,当我打印jar的用法声明时,我想显示以下内容:
I've created an executable jar and using commons-cli to give the user the ability to specify command line parameters when he launches the client. Everything works fine. However, when I print the usage statement for the jar, I would like to show the following:
usage: java -jar myprog.jar <options> <file>
--help Display the help message
--debug Enable debugging
....
使用commons-cli可以轻松打印所有选项.但是,用法"行是头部刮擦器.我似乎无法找出从传递给应用程序的args []中获取"myprog.jar"名称的方法.
Printing of all the options is easily done with commons-cli. However, the "usage" line is the head scratcher. I cannot seem to figure out a way to get the "myprog.jar" name from the args[] that are passed to the application.
有没有简单的方法可以做到这一点?我可以使用一个复杂的方法从类的类加载器中返回跟踪信息,并弄清它是否包含在jar中,但是对于应该是一个非常简单的问题来说,这似乎是一个相当丑陋的答案.
Is there any easy way of doing this? I could use a pretty convoluted method to back trace from my class' classloader and figure out if it is contained within a jar, but that seems like a fairly ugly answer to what should be a pretty simple question.
private String getPath(Class cls) {
String cn = cls.getName();
String rn = cn.replace('.', '/') + ".class";
String path =
getClass().getClassLoader().getResource(rn).getPath();
int ix = path.indexOf("!");
if(ix >= 0) {
return path.substring(0, ix);
} else {
return path;
}
}
推荐答案
在这里:
new java.io.File(SomeClassInYourJar.class.getProtectionDomain()
.getCodeSource()
.getLocation()
.getPath())
.getName()
编辑:我看到了您对getSourceCode API的评论.好吧,这可能是用Java可以做到的最好的事情.关于getCodeSource()
返回null
的问题,我认为它主要发生在java.lang.*
中的类和其他源"隐藏在其上的特殊类中.不过应该适合您自己的班级.
I saw your comment about getSourceCode API. Well, this is probably the best you can do in Java. About getCodeSource()
returning null
, I think it mainly happens on classes in java.lang.*
and other special classes for which the source location is "hidden". Should work for your own classes though.
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