如何为调试和发布版本配置我的makefile? [英] How can I configure my makefile for debug and release builds?

问题描述

我的项目有以下makefile，我想对其进行配置以进行发布和调试.在我的代码中，我有很多#ifdef DEBUG宏，因此只需设置此宏并将-g3 -gdwarf2标志添加到编译器即可.我该怎么办?

I have the following makefile for my project, and I'd like to configure it for release and debug builds. In my code, I have lots of #ifdef DEBUG macros in place, so it's simply a matter of setting this macro and adding the -g3 -gdwarf2 flags to the compilers. How can I do this?

$(CC) = g++ -g3 -gdwarf2
$(cc) = gcc -g3 -gdwarf2

all: executable

executable: CommandParser.tab.o CommandParser.yy.o Command.o
    g++ -g -o output CommandParser.yy.o CommandParser.tab.o Command.o -lfl

CommandParser.yy.o: CommandParser.l 
    flex -o CommandParser.yy.c CommandParser.l
    gcc -g -c CommandParser.yy.c

CommandParser.tab.o: CommandParser.y
    bison -d CommandParser.y
    g++ -g -c CommandParser.tab.c

Command.o: Command.cpp
    g++ -g -c Command.cpp

clean:
    rm -f CommandParser.tab.* CommandParser.yy.* output *.o

为了澄清，当我说发布/调试版本时，我希望能够只键入make并获得发布版本或make debug并获得调试版本，而无需手动注释makefile中的内容.

Just to clarify, when I say release/debug builds, I want to be able to just type make and get a release build or make debug and get a debug build, without manually commenting out things in the makefile.

推荐答案

您可以使用请记住在所有编译命令中都使用$(CXX)或$(CC).

Remember to use $(CXX) or $(CC) in all your compile commands.

然后，"make debug"将具有-DDEBUG和-g之类的额外标志，而"make"则不会.

Then, 'make debug' will have extra flags like -DDEBUG and -g where as 'make' will not.

顺便提一句，您可以像其他帖子所建议的那样使Makefile更加简洁.

On a side note, you can make your Makefile a lot more concise like other posts had suggested.

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