如何将发布目标添加到Makefile? [英] How to add release target to Makefile?

问题描述

我有以下Makefile，我想将其配置为默认生成调试版本，并通过指定相应的目标来释放版本.

I have following Makefile, and I would like to configure it to produce debug build by default and release build by specifying corresponding target.

我现在要解决的问题是-项目包含单元测试，我希望它们包含在默认版本中，但不包含在发行版中，因此我将发行版目标添加到了Makefile中:

The problem I am trying to solve right now is following, - project contains unit tests, and I want them to be included in default build, but excluded from release, so I am added release target to Makefile:

FC      = ifort
FFLAGS  = -c -free -module modules -g3 -warn all -warn nounused
LDFLAGS = -save-temps -dynamiclib

INTERFACES = src/Foundation.f units/UFoundation.f units/Asserts.f units/Report.f
EXCLUDES   = $(patsubst %, ! -path './%', $(INTERFACES))
SOURCES    = $(INTERFACES) \
             $(shell find . -name '*.f' $(EXCLUDES) | sed 's/^\.\///' | sort)
OBJECTS    = $(patsubst %.f, out/%.o, $(SOURCES))
EXECUTABLE = UFoundation

all: $(SOURCES) $(EXECUTABLE)

release: SOURCES := $(filter-out units/%.f, $(SOURCES))
release: OBJECTS := $(filter-out units/%.o, $(OBJECTS))
release: EXECUTABLE := 'Foundation.dlyb'
release: $(EXECUTABLE)

$(EXECUTABLE): $(OBJECTS)
    @echo 'Linking to $@...'
    @$(FC) $(LDFLAGS) $(OBJECTS) -o out/$@

out/%.o: %.f
    @echo 'Compiling $@...'
    @mkdir -p modules
    @mkdir -p $(dir $@)
    @$(FC) $(FFLAGS) -c $< -o $@

clean:
    @echo "Cleaning..."
    @rm -rf modules out $(EXECUTABLE)

不幸的是，这无济于事-'make'和'make release'的结果相同(make release编译默认情况下的单元测试文件).我已经看过类似的问题，例如如何我为调试和发布版本配置了我的makefile吗?，但是解决该问题没有成功.

Unfortunate, it doesn't help - result of 'make' and 'make release' are the same (make release compiles unit test files as in default). I already looked to similar questions, like How can I configure my makefile for debug and release builds?, but without any success to solve the issue.

推荐答案

使用不同的宏(例如NDEBUG)和不同的优化级别来构建调试和发布目标.通常，您不希望混合使用调试和发行目标文件，因此需要将它们编译到不同的目录中.

Debug and release targets get build with different macros (e.g. NDEBUG) and different optimization levels. You normally do not want to mix debug and release object files, hence they need to be compiled into different directories.

我经常通过这种方式将不同的顶层构建目录用于不同的构建模式:

I often use a different top-level build directory for different build modes this way:

BUILD := debug
BUILD_DIR := build/${BUILD}

然后编译器以这种方式进行标记:

And compiler flags this way:

cppflags.debug :=
cppflags.release := -DNDEBUG
cppflags := ${cppflags.${BUILD}} ${CPPFLAGS}

cxxflags.debug := -Og
cxxflags.release := -O3 -march=native
cxxflags := -g -pthread ${cxxflags.${BUILD}} ${CXXFLAGS}

然后将您的对象构建到BUILD_DIR.

And then build your objects into BUILD_DIR.

当您以make BUILD=release调用它时，它将覆盖在makefile中进行的BUILD := debug分配.

When you invoke it as make BUILD=release that overrides BUILD := debug assignment made in the makefile.

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