每次执行前提条件 [英] Execute make prerequisite every time

问题描述

我的制作文件:

.PHONY: test-unit test-functional mocha

test: test-unit test-functional

test-unit: SUITE = "unit"
test-unit: mocha
    @echo "unit"

test-functional: SUITE = "functional"
test-functional: mocha
    @echo "functional"

mocha:  
    @echo ===== RUNNING TESTS: $(SUITE) =====

我想使用此makefile来运行我的两个测试套件，而不必复制运行套件所需要的代码(抽象到mocha任务中).但是，Make很聪明，意识到test-functional在test-functional上已经运行了，因此不再运行.

I'd like to use this makefile to run both of my test suites without duplicating the code for what it takes to run a suite (abstracted into the mocha task). However, Make is being smart and realizes that mocha has already been run when it comes to test-functional and doesn't run it again.

make test:

===== RUNNING TESTS: unit =====
unit
functional

是否有更好的方法来实现类似的抽象，或者将mocha标记为需要每次运行?

Is there a better way to approach this perhaps to achieve similar abstraction, or perhaps flag mocha as needing to be run every time?

推荐答案

使用mocha任务的正文的"nofollow>罐装食谱，并将其粘贴在两个测试任务中.

Use a Canned Recipe for the body of the mocha task and stick it in both test tasks.

代替

mocha:
    @echo ===== RUNNING TESTS: $(SUITE) =====

test: mocha

使用

define mocha
@echo ===== RUNNING TESTS: $(SUITE) =====
endef

test:
    $(mocha)
    ....

我相信

define mocha =(或:=等)要达到4.0以上.

define mocha = (or := etc.) for make 4.0+ I believe.

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