SQL Server查询多对多关系 [英] SQL Server Query for Many to Many Relationship
问题描述
我的SQL Server中具有以下多对多关系(请参见下图).
I have the following Many to many relationship (See the picture below) in my SQL server.
在大多数情况下,表tblWavelengths中有2行与表tblSensors相关(在某些情况下只有1行,在极端情况下可能有20行)
In most cases there's are 2 rows in table tblWavelengths related to the table tblSensors, (in some cases only 1, and in extreme cases there can be 20 rows)
我进行了以下简单查询,以从这3个表中检索数据:
I made the following simple query to retrieve the data from those 3 tables :
select W.DateTimeID,S.SensorName,S.SensorType,W.Channel,W.PeakNr,W.Wavelength
from tblWavelengths as W
Left Join tblSensorWavelengths as SW on W.tblWavelengthID = SW.WavelengthID
Left Join tblSensors as S on SW.SensorID = S.SensorID
order by W.DateTimeID
运行此查询后,我得到以下结果:
After running this query I got the following results :
这是我的问题.我想编写一个查询,该查询仅过滤那些在给定时间点(DateTimeID)在tblWavelengths表中具有两行(两种不同波长)的传感器(SensorName).因此,例如,我希望得到的结果没有 77902/001传感器-因为在给定的时间点只有一排(一个波长)与tblSensors相关
Here comes my problem. I want to write a query which filters only those Sensors (SensorName) which at a given moment in time (DateTimeID) has two rows (two different wavelengths) in the tblWavelengths table. So for example I want to have the results without the 77902/001 Sensor - because it has only one row (one Wavelength) related to the tblSensors at a given moment in time
推荐答案
您可以使用窗口化函数找出每种传感器名称/日期时间组合的波长数:
You could use a windowed function to find out the number of wavelengths for each sensorname/datetimeid combination:
WITH Data AS
( SELECT W.DateTimeID,
S.SensorName,
S.SensorType,
W.Channel,
W.PeakNr,
W.Wavelength,
[Wcount] = COUNT(*) OVER(PARTITION BY s.SensorName, d.DateTimeID)
from tblWavelengths as W
LEFT JOIN tblSensorWavelengths as SW
ON W.tblWavelengthID = SW.WavelengthID
LEFT JOIN tblSensors as S
ON SW.SensorID = S.SensorID
)
SELECT DateTimeID, SensorName, SensorType, Channel, PeakNr, WaveLength
FROM Data
WHERE Wcount = 2
ORDER BY DateTimeID;
添加
经过一番思考,我意识到您可能同时为一个传感器使用相同的波长获得两个结果,这将返回2条记录,但是没有两个不同的波长.由于窗口函数不支持DISTINCT
的使用,因此下面提供了一种替代方法
As an after thought I realised that you might have two results for one sensor at the same time with the same wavelength, which would return 2 records, but not have two different wavelengths. Since windowed functions don't support the use of DISTINCT
an alternative is below
WITH Data AS
( SELECT W.DateTimeID,
S.SensorName,
S.SensorType,
W.Channel,
W.PeakNr,
W.Wavelength,
W.tblWaveLengthID
from tblWavelengths as W
LEFT JOIN tblSensorWavelengths as SW
ON W.tblWavelengthID = SW.WavelengthID
LEFT JOIN tblSensors as S
ON SW.SensorID = S.SensorID
)
SELECT d.DateTimeID, d.SensorName, d.SensorType, d.Channel, d.PeakNr, d.WaveLength
FROM Data d
INNER JOIN
( SELECT DateTimeID, SensorName
FROM Data
GROUP BY DateTimeID, SensorName
HAVING COUNT(DISTINCT tblWaveLengthID) = 2
) t
ON t.DateTimeID = d.DateTimeID
AND t.SensorName = d.SensorName
ORDER BY d.DateTimeID;
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