如何为该多对多表建立SQL查询? [英] How do I establish a SQL query for this many-to-many table?
问题描述
我正在使用PHP/MySQL在此站点中构建此以物易物类型的函数,并且我试图创建一个查询并使用以下字段进行响应: 所有者的用户名,标题,要约人的用户名,要约人的项目
I'm building this bartering-type function in this site using PHP/MySQL and I'm trying to create a query that responds with the following fields: owner's username, title, offerer's username, offerer's item
基本上,我在这里有三个带有以下字段的表:
Basically I have three tables here with the following fields:
用户
user_id, username, email
items_available
item_number, owner_id (foreign key that links to user_id), title
offers_open
trade_id, offerers_id (fk of user_id), offerers_item(fk with item_number), receivers_id (fk from user_id)
我该怎么做?我已经看到了对多对多SQL查询的一些引用,但是它们似乎并不特别适合我要查找的内容(例如,offerers_id和owner_ids在Users表中引用了不同的users_id,但该怎么做)我在sql查询中使它们与众不同吗?)
How do I do this? I've seen some references to many-to-many SQL queries but they don't seem to particularly fit what I'm looking for (for example, the offerers_id and the owner_ids refer to different users_id in the Users table, but how do I make them distinguishable in the sql query?)
推荐答案
如果我正确理解,这就是您要寻找的东西:
If I understand correctly, this is what you are looking for:
SELECT owner.username, oferrers.username, ia.title
FROM offers_open o
INNER JOIN users AS offerers
ON o.offerers_id = offerers.user_id
INNER JOIN items_available AS ia
ON o.offerers_item= ia.item_number
INNER JOIN users AS owner
ON ia.owner_id = owner.user_id
我没有在users
表格上看到标题,因此没有包含标题.
I don't see a title on the users
table, so didn't include one.
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