OpenERP:创建新记录，一对多关系 [英] OpenERP : create new record ,one2many many2one relationship

问题描述

我已经在A类和其他字段nombre(整数)中创建了on2many字段:

I have created on2many field in class A and other field nombre (integer):

'Inventaire' : fields.one2many('class.b','id_classb'),

'nombre' : fields.integer('Nombre'),

在b类中:

'id_classb' : fields.many2one('class.a', 'ID_classA'),

'ql' : fields.integer('QL'),

我想在a类中创建一个函数，根据nombre字段的值为对象b创建记录.例如，如果nombre = 3，我应该创建3个b类的对象

I want to create a function in class a that create records for object b according to the value of nombre field. for example if nombre =3 I should create 3 object of class b

这是我的功能:

 def save_b(self, cr, uid, ids, field_name, arg, context):
  a= self.browse(cr, uid, id)
  nbr=a.nombre
  num=22
  for i in range(nbr):
       num+=1
       self.create(cr, uid, [(0, 0,{'ql':num})])

我得到这些错误: TypeError:range()预期为整数，没有NoneType ValueError:字典更新序列元素#0的长度为3；需要2个

I get these errors : TypeError:range()integer expected ,got NoneType ValueError: dictionary update sequence element #0 has length 3; 2 is required

有人可以帮助我改善我的功能吗?

can someone help me to improve my function?

推荐答案

您遇到以下错误:

1. 您的create调用值应该是一个以字段名作为键的字典，而不是包含元组的列表.您正在使用的表示法是用于编写/更新一个或多个字段.

1. Your create call values should be a dictionary with field names as keys, not a list with tuples. The notation you are using is for writing/updating one2many fields.

您不是在创建"b类"记录，而是在创建"a类"记录(使用self而不是self.pool.get调用)

You are not creating 'class b' records, but creating 'class a' records instead (using self instead of a self.pool.get call)

所以你应该写

def save_b(self, cr, uid, ids, field_name, arg, context):
    b_obj = self.pool.get('class.b') # Fixes (#2)
    for record in self.browse(cr, uid, ids, context=context):
        num = 22
        for i in range(record.nombre):
            num += 1
            new_id = b_obj.create(cr, uid, {
                'ql': num,
                'id_classb': record.id
            }, context=context) # Fixes (#1)

或者作为替代:

def save_b(self, cr, uid, ids, field_name, arg, context):
    for record in self.browse(cr, uid, ids, context=context):
        sub_lines = []
        num = 22
        for i in range(record.nombre):
            num += 1
            sub_lines.append( (0,0,{'q1': num}) )
            # Notice how we don't pass id_classb value here,
            # it is implicit when we write one2many field
        record.write({'Inventaire': sub_lines}, context=context)

备注:在类b中，您到类a的链接在名为'id_classb'的列中? openerp礼节希望您将其命名为"classa_id"或类似名称.

Remark: In class b your link to class a is in column named 'id_classb'? The openerp-etiquette expects you to name them 'classa_id' or something similar.

另外，用大写字母创建列名称的想法也不受欢迎.

Also, creating column names with capitals is frowned upon.

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