python字典:如何获取具有特定值的所有键 [英] python dictionary: How to get all keys with specific values

问题描述

是否可以将字典中的所有键的值都超过阈值?

Is it possible to get all keys in a dictionary with values above a threshold?

一本字典的样子:

mydict = {(0,1,2):"16",(2,3,4):"19"}

例如，阈值可能是17

The Threshold could be 17 for example

推荐答案

当然可以.我们可以简单地写:

Of course it is possible. We can simply write:

[k for k,v in mydict.items() if float(v) >= 17]

或者在您使用python的情况下-2.7 ，您-喜欢

Or in the case you work with python-2.7, you - like @NoticeMeSenpai says - better use:

[k for k,v in mydict.iteritems() if float(v) >= 17]

这是列表理解.我们遍历mydict词典中的键值对.接下来，将值v转换为float(v)，并检查该float是否大于或等于17.如果是这种情况，我们将键k添加到列表中.

This is a list comprehension. We iterate through the key-value pairs in the mydict dictionary. Next we convert the value v into a float(v) and check if that float is greater than or equal to 17. If that is the case, we add the key k to the list.

对于给定的mydict，它会生成:

For your given mydict, this generates:

>>> [k for k,v in mydict.items() if float(v) >= 17]
[(2, 3, 4)]

因此包含满足以下条件的单键的列表:(2,3,4).

So a list containing the single key that satisfied the condition here: (2,3,4).

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