从字符串向字典分配键 [英] Assigning keys to a dictionary from a string
问题描述
我有一个名为sentence
的字符串:'the sly fox jumped over the brown dog'
I have a string called sentence
: 'the sly fox jumped over the brown dog'
我需要创建一个名为Positions
的字典.
Positions
的键应为sentence
中的字符.
这些值应该是这些字符的索引.
I need to create a dictionary called Positions
.
The keys for Positions
should be the characters in sentence
.
The values should be the index for those characters.
例如,所需的输出将是:
For example the desired output would be:
{'t':0, 'h':1, 'e':2, ' ':3 ...}
等,等等.
我当然可以手动将其写出,但实际上我被要求将字符串转换为键,而无需手动将其写出.
Of course I can write this out manually, but I think I'm actually being asked to convert the string into keys without writing them out manually.
到目前为止,我刚刚创建了一个空字典,并尝试在事件之后为其分配键和值:
So far I've just created an empty dictionary and am trying to assign keys and values to it after the event:
Positions = {}
我是从错误的脚开始吗?
Have I started off on the wrong foot?
推荐答案
您可以执行以下操作:
result = {}
s = 'the sly fox jumped over the brown dog'
for i, c in enumerate(s):
result.setdefault(c, []).append(i)
print(result)
输出
{'m': [14], 'e': [2, 16, 21, 26], 'v': [20], 's': [4], 'n': [32], 'h': [1, 25], 'w': [31], 'l': [5], 'o': [9, 19, 30, 35], 'x': [10], 'p': [15], 'd': [17, 34], 'g': [36], 't': [0, 24], 'u': [13], 'f': [8], 'y': [6], 'b': [28], 'j': [12], ' ': [3, 7, 11, 18, 23, 27, 33], 'r': [22, 29]}
请注意,上述解决方案考虑了重复字符的大小写,并创建了索引列表.
Note that the above solution contemplates the case for repeated characters and it creates a list of the indices.
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