是否可以创建字典“模板"? [英] Is it possible to create a dictionary "template"?

问题描述

我正在创建各种食谱选择器，并希望创建一个统一的字典模板.我目前有这样的东西:

I'm creating a recipe selector of sorts and am looking to create a unified dictionary template. I currently have something like this:

menu_item_var = {'name': "Menu Item", 'ing': (ingredients)}

出于时间的考虑，我担心要为每个menu_item_var重新键入name和ing，并可能造成误输入.我知道我可以将Menu Item添加为tuple,中的项目0，并擦除dict并运行for循环以使字典更安全，但这不会从tuple转换原始的menu_item_var到dict.有没有一种更智能"的方式来做到这一点?

I'm concerned about retyping name and ing for every menu_item_var, for time's sake and the likely disaster of a mis-key. I know I could add Menu Item as item 0 in my tuple, erase the dict and run a for loop to make the dictionaries safer, but that wouldn't convert the original menu_item_var from a tuple to dict. Is there a "smarter" way of doing this?

推荐答案

我可能建议您考虑创建一个类，并使用OOP代替类似的东西.

I'd probably suggest looking at creating a class and using OOP instead for something like this.

class Recipe:
    def __init__(self,name,ingredients):
        self.name = name
        self.ingredients = ingredients
    def __str__(self):
        return "{name}: {ingredients}".format(name=self.name,ingredients=self.ingredients)

toast = Recipe("toast",("bread"))
sandwich = Recipe("sandwich",("bread","butter","ham","cheese","butter","bread"))

随着您的模板"变得越来越复杂，它不仅仅是一个数据定义，而且需要逻辑.使用类可以封装它.

As your "template" get more and more complex, it becomes more than just a data definition and requires logic. Using a Class will allow you to encapsulate this.

例如，我们的三明治上方有2个面包和2个黄油.我们可能希望在内部对此进行跟踪，如下所示:

For example, above our sandwich has 2 breads and 2 butters. We might want to keep track of this internally, like so:

class Recipe:
    def __init__(self,name,ingredients):
        self.name = name
        self.ingredients = {}
        for i in ingredients:
            self.addIngredient(i)
    def addIngredient(self, ingredient):
        count = self.ingredients.get(ingredient,0)
        self.ingredients[ingredient] = count + 1
    def __str__(self):
        out =  "{name}: \n".format(name=self.name)
        for ingredient in self.ingredients.keys():
            count = self.ingredients[ingredient]
            out += "\t{c} x {i}\n".format(c=count,i=ingredient)
        return out

sandwich = Recipe("sandwich",("bread","butter","ham","cheese","butter","bread"))
print str(sandwich)

哪个给了我们

sandwich:
    2 x butter
    1 x cheese
    1 x ham
    2 x bread

这篇关于是否可以创建字典“模板"?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！