如何在R中递归Map()函数(通过嵌套列表)? [英] How to Map() a function recursively (through nested lists) in R?
问题描述
免责声明:这不是此问题的重复项: 如何组合rapply()和mapply(),或如何递归使用mapply/Map? 在这个问题之上,我在问如何将额外的函数参数合并到递归中.
Disclaimer: this is not a duplicate of this question: How to combine rapply() and mapply(), or how to use mapply/Map recursively? On top of that question, I am asking how to incorporate extra arguments of functions into the recursion.
所以我有列表:
A = list(list(list(c(1,2,3), c(2,3,4)),list(c(1,2,3),c(2,3,4))), list(c(4,3,2), c(3,2,1)))
B = list(list(list(c(1,2,3), c(2,3,4)),list(c(1,2,3),c(2,3,4))), list(c(4,3,2), c(3,2,1)))
我需要递归地对其应用不同的功能,以保留列表结构.大概,当该函数为mean()时,执行此操作的递归函数将如下所示:
And I need to apply different functions to it recursively that preserves the list structure. Presumably, a recursive function that does this goes like this, when the function is mean():
recursive = function(x, y){
if(is.null(y)){
if(is.atomic(x)){
x*x
} else{
Map(recursive, x)
}
} else{
if(is.atomic(y) && is.atomic(x)){
x*y
} else{
Map(recursive, x, y)
}
}
}
因此,期望的结果将是:
So the desired result would be:
recursive(A,B)
我想知道如何将这种递归推广到除硬编码的function(x,y) x*y
之外的任何函数,以便我可以方便地更改函数?
在这种情况下,它将以以下内容开头:
I was wondering how could I generalize this recursion to any functions beyond just the hard-coded function(x,y) x*y
here so that I could change functions conveniently?
In that case, it would start with:
recursive = function(somefunction, x, y){
....
}
其中
somefunction = function(x,y) x*y #or any other function taking x and y as inputs
有人可以给我一个出路吗?非常感谢.
Could anyone kindly show me a way out? Thank you so much.
推荐答案
您可以使用
recursive <- function(fun, x, y) {
if(is.atomic(x) && is.atomic(y)) {
match.fun(fun)(x, y)
} else {
Map(recursive, x, y, MoreArgs=list(fun=fun))
}
}
原因是Map
调用mapply
,并且mapply
具有MoreArgs=
参数,您可以在其中指定要传递给不想迭代的调用函数的其他参数.
The reason is that Map
calls mapply
and mapply
has a MoreArgs=
parameter where you can specify other parameters you want to pass to the calling function that you do not want to iterate over.
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