读取文本文件并在python中形成字典 [英] Read a text file and form a dictionary in python
本文介绍了读取文本文件并在python中形成字典的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有data.txt文件,在python代码下面读取文本并形成字典.
I have file data.txt , below python code reads a text and forms dictionary.
文件:data.txt
file: data.txt
10/20 vinay
05/31 hunachyal
11/23 mine
bday_list = {}
infile = open("data.txt")
for line in infile:
List_array = [w.strip() for w in line.split("\t")]
bday_list[List_array[0]] = List_array[1]
# print line
print bday_list
Op: {'11/23': 'mine', '10/20': 'vinay', '05/31': 'hunachyal'}
类似地,如何以OP中所示的格式获取以下文件的判别力
Similarly how to get dictinaory for the below file in the format as shown in OP
文件
10/20 Name vinay phone +91094xxx
05/31 Name hunachyal phone +91jndjxx
11/23 Name mine phone +92jdddxxx
OP:
{'11/23': {'Phone': '+91kexxx', 'Name': 'mine'}, '10/20': {'Phone': '+919xxxx', 'Name': 'vinay'}, '05/31': {'Phone': '+9194xxxx', 'Name': 'hunachyal'}}
或者python中是否有任何方法可以形成数据库,以便我可以轻松获取数据.
Or Is there any method in python to form data base where i can easily fetch data .
推荐答案
您也可以尝试
bday_list = {}
with open('data.txt', 'r') as R:
for line in R:
l = line.strip().split() # split the line to list
bday_list[l[0]] = {k:v for k,v in zip(l[1::2], l[2::2])}
PS,
如果您使用的是infile = open(...)
而不是with open() as infile:
来处理文件句柄,则应该记住之后要close
文件句柄.
PS,
If you are using infile = open(...)
and not with open() as infile:
to work with a file handle, you should remember to close
the file handle afterward.
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