python模式具有至少一个键 [英] python schema to have at least one key

问题描述

我正在使用> schema 库.

如何创建模式以验证字典中是否包含任何键和相应的值?

How can I create a schema to validate if a dictionary contains anyone of the keys and corresponding values in it?

mydict_schema = Schema({
    Optional('name'): str,
    Optional('name_id'): int,
})

目前所有键都是Optional，但我希望至少有一个.

At the moment the keys are all Optional, but I want there to be at least one of them.

推荐答案

上下文

• python2
• 使用架构库进行验证
• DevSyedK想创建一个模式验证约束，该约束要求字典从一组可能的键中至少拥有一个键
• DevSyedK当前具有ZeroOrMore约束，但DevSyedK希望它成为OneOrMore约束
• DevSyedK wants to create a schema validation constraint that requires a dictionary to have at least one key from a set of possible keys
• DevSyedK currently has a ZeroOrMore constraint, but DevSyedK wants it to be a OneOrMore constraint
• 建立两个列表，一个列表包含所有可能的密钥，另一个列表包含要验证的数据中包含的实际密钥
• 创建模式约束，当且仅当两个列表的交集为非空时才返回True

• 注意:这不是问题的完整解决方案，只是概念证明.

• Note: this is not a complete solution to the question, just a proof-of-concept.

lstkeys_possible  = ['alpha','bravo','charlie']
lstkeys_actual    = []   ## wont validate
lstkeys_actual    = ['zulu']  ## wont validate
lstkeys_actual    = ['alpha']  ## will validate
Schema( lambda vinput: bool(set(vinput[0]) & set(vinput[1])) ).validate( [lstkeys_possible,lstkeys_actual] )

• 如何查找列表交集?

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